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2 years ago

Which equation can be used to solve the problem? 10 is 50 percent of what number?

2 answers:

7 0

10 is 50 percent of what number? StartFraction 10 divided by 1 Over 50 divided by 1 EndFraction = StartFraction 10 Over 50 EndFraction StartFraction 100 times 2 Over 50 times 2 EndFraction = StartFraction 200 Over 100 EndFraction

Rudiy272 years ago

3 0

Answer:

x*50%=10

Step-by-step explanation:

x*50%=10

/50% /50%

x=20

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Identify the sequence graphed below and the average rate of change from n = 1 to n = 3.

dsp73

Answer:

The required sequence is $a_n=20(\frac{1}{2})^{n-1}$ . The average rate of change from n = 1 to n = 3 is -7.5.

Step-by-step explanation:

From the given graph it is clear that the sequence is a GP because the all terms are half of their previous terms.

Here, $a_2=10,a_3=5,a_4=2.5,a_5=1.25$

$r=\frac{a_3}{a_2}=\frac{5}{10}=\frac{1}{2}$

The common ratio of GP is 1/2.

$r=\frac{a_2}{a_1}$

$\frac{1}{2}=\frac{10}{a_1}$

$a_1=20$

The first term of the sequence is 20.

The formula for sequence is

$a_n=a(r)^{n-1}$

Where a is first term and r is common difference.

The required sequence is

$a_n=20(\frac{1}{2})^{n-1}$

The formula for rate of change is

$m=\frac{f(x_2)-f(x_1)}{x_2-x_1}$

The average rate of change from n = 1 to n = 3 is

$m=\frac{f(3)-f(1)}{3-1}$

$m=\frac{5-20}{3-1}$

$m=\frac{-15}{2}=-7.5$

Therefore the required sequence is $a_n=20(\frac{1}{2})^{n-1}$ . The average rate of change from n = 1 to n = 3 is -7.5.

8 0

3 years ago

Read 2 more answers

Given a=4,b=-2 and c=8, evaluate -|b-a|<br><br> -2<br> -6<br> 6

Salsk061 [2.6K]

Answer: -6

Step-by-step explanation: -|b-a|

-|-2-4|

-|-6|

-6

Once you get rid of the absolute value bars the negative sign is still outside of them making 6 negative again. Hope this helped! :P

5 0

3 years ago

Read 2 more answers

How long would it take you to double your money is the bank pays 3.6% interest, compounded

Lapatulllka [165]

Answer:

$t=19.25\ years$

Step-by-step explanation:

we know that

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$t=?\ years\\P=x\\r=3.6\%=3.6/100=0.036\\A=2x$

substitute in the formula above

$2x=x(e)^{0.036t}$

solve for t

simplify

$2=(e)^{0.036t}$

Apply ln both sides

$ln(2)=ln[(e)^{0.036t}]$

Applying property of exponents

$ln(2)=[0.036t]ln(e)$

Remember that ln(e) =1

$ln(2)=[0.036t]$

$t=ln(2)/[0.036]$

$t=19.25\ years$

7 0

3 years ago

What is the answer too 3-3*6 2=?

liq [111]

3-(3x62)=
3x62=186-3=183

7 0

2 years ago

253,248,243, find the 49th term.

denpristay [2]

Answer:

Step-by-step explanation:

the difference is -5

nth=a+(n-1)d
a=253,n=49,d=5
253+(49-1)×-5
253+48×-5
253+(-240)
253-240=13

the 49th term is 13

8 0

2 years ago