Hello from MrBillDoesMath!
Answer:
x = 1/2 (1 +\- i sqrt(23))
Discussion:
x \3x - 2 = (x/3)*x - 2 = (x^2)/3 - 2 (*)
1 \3x - 4 = (1/3)x - 4 (**)
(*) = (**) =>
(x^2)/3 -2 = (1/3)x - 4 => multiply both sides by 3
x^2 - 6 = x - 12 => subtract x from both sides
x^2 -x -6 = -12 => add 12 to both sides
x^2-x +6 = 0
Using the quadratic formula gives:
x = 1/2 (1 +\- i sqrt(23))
Thank you,
MrB
He did this then that plus to this and that =334.2
Answer:
2.5
Step-by-step explanation:
Answer:

Step-by-step explanation:
Given that when you add two numbers together the result is 3.
The greater of the number is given as a.
Let "x" represent that lesser number.
Thus:

To make x the subject of the formula. Subtract a from both x.


Therefore, the expression that represents the lesser number, x, is:

Comment:
Then how does that work
Step-by-step explanation: