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statuscvo [17]
3 years ago
8

Dina planted a six-foot tree in her backyard which she expects to grow at the rate of 4 feet per year. Find the equation of the

line that shows how tall the tree will be each year, then use your equation to find out how tall the tree will be 4 years after she plants it. Let x - the number of years since she planted the tree; let y = the height of the tree in feet. Explain your solution and show me your work in arriving at your responses.
Mathematics
1 answer:
Scrat [10]3 years ago
8 0

Answer:

y = 6 + 4x

After 4 years, the tree would be 22 ft tall.

Step-by-step explanation:

Hi there!

Let x = the number of years that pass

Let y = the height of the tree (ft)

We're given that the 6-foot tree grows at a rate of 4 ft per year. This means that the height of the tree will be equal to 6 ft, the original height, plus another 4 ft every year that passes.

Height of tree = 6 feet + 4 feet × number of years that pass

y = 6 + 4x

To solve for how tall the tree would be 4 years after Dina plants it, replace x with 4, since 4 years have passed:

y = 6 + 4(4)

y = 6 + 16

y = 22

Therefore, the tree would be 22 ft tall.

I hope this helps!

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Dafna11 [192]
They can ride their bike 12 miles because in 6 minutes they ride 0.8 miles so in 1.5 hours they ride 12 miles. 0.8 * 10 = 8 miles 1 hour so 0.8 * 5 = 4 miles 0.5 hours            8 miles + 4 miles =12 miles           1 hour + 0.5 hours = 1.5 hours
7 0
3 years ago
F(x)=x^2-3x-2 is shifted 4 units right. The result is g(x). What is g(x)?
-BARSIC- [3]

Answer:

\boxed{\mathrm{C.}\:\: g(x)=(x-4)^2-3(x-4)-2}

Step-by-step explanation:

The function is shifted 4 units right.

The value of x in the function is subtracted from 4, because this is a horizontal translation.

f(x)=x^2-3x-2

g(x)=(x-4)^2-3(x-4)-2

8 0
3 years ago
Read 2 more answers
Please help me on this problem​
Rudik [331]
<h2><em><u>Answer:</u></em></h2>

Total Surface Area = 375 ft^2

<h2><em><u>Step-by-step explanation:</u></em></h2>

You need to find the area of the ceiling, floor, the two rectangle walls and the two trapezoid walls

<u>Area of the ceiling:</u>

c = length * width

c = 9*6.5 = 58.5

<u>Area of the 2 rectangle walls:</u>

w = 2(length * width)

w = 2(9 * 8)

w = 2(72)

w = 144

<u>Area of floor:</u>

f = 9 * 7.5

f = 67.5

<u>Area of the two trapezoids:</u>

t = 2(h * \frac{a + b}{2})

a = 6.5

b = 7.5

h = 7.5

t = 2(h * \frac{a + b}{2})

t = 2(7.5 * \frac{6.5 + 7.5}{2})

t = 2(7.5 * \frac{14}{2})

t = 2(7.5 * 7)

t = 2(52.5)

t = 105

Total Surface Area = c + w + f + t

Total Surface Area = 58.5 + 144 + 67.5 + 105

Total Surface Area = 375 ft^2

8 0
4 years ago
Anyway you can help me out?
Trava [24]
Okay, so to get the inverse function, you need to isolate the x first.

You can do this by multiplying by 4. Then, -2 to get just 3x and finally divide by 3 so that you just have x on its own. If we write this all out, we get (4x-2)/3.

Next, we need to substitute 24 into x's place. So, we have ((4x24)-2)/3. Then, we can just simplify. 4x24=96. 96-2=94. 94/3=32.6.

Hope this helps :)
8 0
3 years ago
What is the domain of the function f(x) =x+1/<br> X^2-6x+8?
SpyIntel [72]

Answer:

The domain of the function is all real values of x, except x = 4 and x = 2

Step-by-step explanation:

We are given the following function:

f(x) = \frac{x+1}{x^2-6x+8}

It's a fraction, so the domain is all the real values except those in which the denominator is 0.

Denominator:

Quadratic equation with a = 1, b = -6, c = 8

Using bhaskara, the denominator is 0 for these following values of x:

\Delta = (-6)^2 - 4(1)(8) = 36-32 = 4

x_{1} = \frac{-(-6) + \sqrt{4}}{2} = 4

x_{2} = \frac{-(-6) - \sqrt{4}}{2} = 2

The domain of the function is all real values of x, except x = 4 and x = 2

8 0
3 years ago
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