All categories

2 years ago

Estimate the quotient . pls help me 19 4/5 ÷ 4 5/8

Mathematics

2 answers:

zaharov [31]2 years ago

7 0

It’s 4
Your welcome lol
4 52/185

elena55 [62]2 years ago

4 0

Answer: The quotient is 4 52/185, which rounds to 4.

Explanation is in the image.

You might be interested in

Time has a total of $28 after spending half of his weekly earnings on a video game and earning $10 additional dollars for mowing

Korolek [52]

Given:

Time has a total of $28 after spending half of his weekly earnings on a video game and earning $10 additional dollars for mowing the lawn.

To find:

Weekly earnings at his part time job.

Solution:

Let x be the weekly earning.

He spend half of his weekly earning, i.e., $\dfrac{x}{2}$

He earns $10 additional dollars for mowing the lawn.

According to the question,

$\dfrac{x}{2}+10=28$

$\dfrac{x}{2}=28-10$

$\dfrac{x}{2}=18$

Multiply both sides by 2.

$x=36$

Therefore, his weekly earnings is $36.

5 0

3 years ago

Which is closest to the volume of a cylinder with a height of 11 inches and

Veseljchak [2.6K]

Answer:

The closest to the volume of cylinder is 63 in.³.

Step-by-step explanation:

Given:

Cylinder with a height of 11 inches and a circumference of 8 1/2 inches.

Now, to find the volume.

As circumference is given we get the radius by putting formula:

Circumference = 8 1/2 inches = 17/2 inches.

Let the radius be $r.$

$Circumference=2\pi r$

Taking the value of π = 3.14.

$\frac{17}{2}=2\times 3.14\times r$

$8.5=6.28\times r$

Dividing both sides by 6.28 we get:

$1.35=r$

So, radius = 1.35 inches.

Height = 11 inches.

Now, putting the formula to get the volume:

$Volume=\pi r^2h$

$Volume=3.14\times 1.35^2\times 11$

$Volume=3.14\times 1.8225\times 11$

$Volume=3.14\times 20.0475$

$Volume=62.949\ inches^3$

Hence, the volume of cylinder = 63 inches³ (approximately).

Therefore, the closest to the volume of cylinder is 63 in.³.

4 0

3 years ago

ANSWER FOR BRAINLIEST:

AlekseyPX

Step-by-step explanation:

I think mode,range and median dpo ako sure

3 0

2 years ago

Help me please i cant get it

Leni [432]

Answer:

Let's define the cost of the cheaper game as X, and the cost of the pricer game as Y.

The total cost of both games is:

X + Y

We know that both games cost just above AED 80

Then:

X + Y > AED 80

From this, we want to prove that at least one of the games costed more than AED 40.

Now let's play with the possible prices of X, there are two possible cases:

X is larger than AED 40

X is equal to or smaller than AED 40.

If X is more than AED 40, then we have a game that costed more than AED 40.

If X is less than or equal to AED 40, then:

X ≥ AED 40

Now let's take the maximum value of X in this scenario, this is:

X = AED 40

Replacing this in the first inequality, we get:

X + Y > AED 80

Replacing the value of X we get:

AED 40 + Y > AED 80

Y > AED 80 - AED 40

Y > AED 40

So when X is equal or smaller than AED 40, the value of Y is larger than AED 40.

So we proven that in all the possible cases, at least one of the two games costs more than AED 40.

7 0

3 years ago

the population of san san Pablo ca is about 33,950 people. ten years ago the population was about 30,000. by what PERCENT did th

azamat

Answer:

ABOUT 13 PERCENT

Step-by-step explanation:

I AM NOT CERTAIN BUT I GOT IT BY:

NEW PRICE - OLD PRICE divided by OLD PRICE X 100

5 0

2 years ago