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2 years ago

High school Geometry

Mathematics

1 answer:

xxTIMURxx [149]2 years ago

6 0

Answer:

the answer is b. sss is not possible

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Simplify the expression below and write it as a single logarithm:

OLEGan [10]

The simplification of 3log(x + 4) – 2log(x – 7) + 5log(x - 2) - log(x^2) is $\log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

<u>Solution:</u>

Given, expression is $3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)$

We have to write in as single logarithm by simplifying it.

Now, take the given expression.

$\rightarrow 3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)$

Rearranging the terms we get,

$\left.\rightarrow 3 \log (x+4)+5 \log (x-2)-2 \log (x-7)+\log \left(x^{2}\right)\right)$

$\text { since a } \times \log b=\log \left(b^{a}\right)$

$\rightarrow \log (x+4)^{3}+\log (x-2)^{5}-\left(\log (x-7)^{2}+\log \left(x^{2}\right)\right)$

$\text { We know that } \log a \times \log b=\log a b$

$\rightarrow \log \left((x+4)^{3} \times(x-2)^{5}\right)-\left(\log \left((x-7)^{2} \times\left(x^{2}\right)\right)\right.$

$\text { We know that } \log a-\log b=\log \frac{a}{b}$

$\rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

Hence, the simplified form $\rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

4 0

3 years ago

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What is the the formula for kite missing height

anastassius [24]

Step-by-step explanation:

In order to calculate the height (distance BC in the diagram) you need to know the distance from point D (the closer of the two measurement points to the kite) to the point directly under the kite, B. Once you know this distance then multiplying this by the tangent of angle b will give you the height.

7 0

2 years ago

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Suppose you are given that p = 2q+1 and that p = 8.

iVinArrow [24]

Answer:

We conclude that the following statements can be proved such as:

$2q+1 = 8$

Step-by-step explanation:

Given the expression

$p = 2q+1$

Given

$p = 8$

IF WE SUBSTITUTE p=2q+1 in p=8

Now, substituting p = 2q+1 in the expression p=8

$p = 8$

$2q+1 = 8$ ∵ p = 2q+1

Therefore, we conclude that the following statements can be proved such as:

$2q+1 = 8$

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3 years ago

A new car was valued at $28,000, and it's value depreciated to $14,000 over the next 3 years. Use the exponential equation for d

kompoz [17]

The exponential equation (in thousands) is:
$V = 28 e^{-rt}$
plug in t=3 yrs, and solve for 'r'.
$14 = 28 e^{-3r} \\ \\ \frac{1}{2} = e^{-3r} \\ \\ ln(\frac{1}{2}) = -3r \\ \\ r = \frac{ln(\frac{1}{2})}{-3} = 0.231 = 23.1%$

Find value of car when t = 10
$V = 28e^{-2.31} = 2.779$

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3 years ago

What is the direct variation equation if y varies directly with x and y= -12 When x= 6?

Setler [38]

If y varies directly with x, then the ratio y/x will always be the same. Set it equal to the known values and solve for y.

y/x = -12/6

Cross multiply

6y = -12x

y = -2x

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3 years ago

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