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ICE Princess25 [194]
3 years ago
13

What is the least common multiple of 50, 60 and 72

Mathematics
1 answer:
Andre45 [30]3 years ago
5 0
The least common multiple of each is 2. 2 x 25= 50. 2 x 30= 60 and 2 x 36=72
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Y&gt;x−4<br> y\ge -\frac{1}{2}x+5<br> y≥− <br> 2<br> 1<br> ​ <br> x+5
8_murik_8 [283]

ANSWER A

STEP BY STEP EXPLANATION

6 0
3 years ago
Line segment AB is dilated to create line segment A’B’ using point Q as the center of dilation what is the scale factor
Alex777 [14]

Answer:

2

Step-by-step explanation:

We are given the distance QA=1.25 and QA'=2.5.

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4 years ago
Yesterday,Bethany sent 60 text messages. she said 15 percent of those messages were to her best friend. How many texts messages
dimulka [17.4K]

Answer:

9

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7 0
3 years ago
Read 2 more answers
John has a roll containing 24 2/3 feet of wrapping paper he wants to divide it into 11 pieces first though he must cut off five
Simora [160]

take 23 2/3 and subtract 6 to get 53/3 or 17 2/3 or 17.667

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6 0
3 years ago
You are to take a multiple-choice exam consisting of 64 questions with 5 possible responses to each question. Suppose that you h
damaskus [11]

Answer:

a) Expected score on the exam is 12.8.

b) Variance 10.24, Standard deviation 3.2

Step-by-step explanation:

For each question, there are only two possible outcomes. Either you guesses the answer correctly, or you does not. The probability of guessing the answer of a question correctly is independent of other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

E(X) = np

The variance of the binomial distribution is:

V(X) = np(1-p)

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

64 questions.

So n = 64

5 possible answers, one correctly, chosen at random:

So p = \frac{1}{5} = 0.2

(a) What is your expected score on the exam?

E(X) = np = 64*0.2 = 12.8

(b) Compute the variance and standard deviation of x. Variance =Standard deviation

V(X) = np(1-p) = 64*0.2*0.8 = 10.24

Variance 10.24

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Standard deviation 3.2

5 0
3 years ago
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