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Marina86 [1]
2 years ago
9

Rewrite the following equation to a real-life word problem: 11p + 12 = 68​

Mathematics
1 answer:
vredina [299]2 years ago
4 0

Step-by-step explanation:

11p+12=68

11p=68-12

11p=56

p=56/11

p=5.9

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Write the percent as a fraction or mixed number in simplest form.
lord [1]

Answer:

\frac{29}{40}

72.5% As a Fraction

= \frac{0.725*1000}{1*1000}

=\frac{725}{1000}

=\frac{725/25}{1000/25}

=\frac{29}{40}

:) I hope this helped you

5 0
3 years ago
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Answer with A B C D. Correct answer gets brainlest.
steposvetlana [31]

Answer:

a

Step-by-step explanation:

the six is the number in the superscript therefore its the exponent

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4 years ago
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Tides are cyclical phenomena caused by the gravitational pull of the sun and the moon. On a particular retaining wall, the ocean
Natasha_Volkova [10]

1.5581 m

Step-by-step explanation:

For every cycle, it takes 6 hours to get from a high to low tide and another 6 hours back to high tide.

The change in the height of the tide in meters is;

2.1 – 0. 8 = 1.3 m

Therefore for every 6 hours, the tides shift by 1.3 meters. The average change is;

1.3 m / 6 hr

= 0.217 m / hr

= 0.00361 m / min

At 9.30 am, the tides are rising from low tides of 6.00 am

9.30 – 6.00 = 3.30

3hrs 30 min

= 210 min

The rise of the tide at this time is by;

0.00361 * 210

= 0.7581 m

The height of the tides will therefore be;

0.8 m + 0.7581m

= 1.5581 m

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3 0
3 years ago
Solve rx = 30 for x.
Tju [1.3M]
Rx = 30...divide both sides by r
x = 30/r <==
3 0
3 years ago
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Find coordinates of the focus, the length of the latus rectum, and the coordinates of its endpoint for y^2= 4x
d1i1m1o1n [39]

Answer:

a) Focus is (1,0)

b) Length of Latus rectum is 4

c) The endpoints of the latus rectum is (1,-2) and (1,2)

Step-by-step explanation:

The given parabola has equation

{y}^{2}  = 4x

When we compare to

{y}^{2}  = 4px

We have

4px = 4x

This implies,

p = 1

The focus of this parabola is at (p,0).

Therefore the focus is (1,0)

b) The length of the latus rectum is given by

|4p|

From a) part we found p to be 1.

Substitute p=1 to obtain:

|4 \times 1|  = 4

c) The focus is the midpoint of the latus rectum.

Since the focus is (1,0), we substitute x=1 into the equation to see intersection of the latus rectum and the parabola.

{y}^{2}  = 4(1)

This means that:

{y}^{2}  = 4

Take square root:

y =  \pm \sqrt{4}

y =  \pm2

y =  - 2 \: or \: y = 2

Therefore the end of latus rectum are at (1,-2) and (1,2)

4 0
3 years ago
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