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3 years ago

Find the real numbers x and y that make the equation true (x+6i)=(3-i)+(4-2yi)

Mathematics

1 answer:

Ronch [10]3 years ago

5 0

Answer:

x = 7

y = -7/2

Step-by-step explanation:

(x+6i)=(3-i)+(4-2yi)

First look at the real parts

x = 3 +4

x = 7

Then look at the imaginary part

6i= -i -2yi

6 = -1-2y

Add 1 to each side

6+1 = -2y

7 = -2y

Divide by -2

7/-2 = y

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3 years ago

Find the real numbers x and y that make the equation true (x+6i)=(3-i)+(4-2yi)​

Find the real numbers x and y that make the equation true (x+6i)=(3-i)+(4-2yi)