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Salsk061 [2.6K]
3 years ago
12

Find the real numbers x and y that make the equation true (x+6i)=(3-i)+(4-2yi)​

Mathematics
1 answer:
Ronch [10]3 years ago
5 0

Answer:

x = 7

y = -7/2

Step-by-step explanation:

(x+6i)=(3-i)+(4-2yi)​

First look at the real parts

x = 3 +4

x = 7

Then look at the imaginary part

6i= -i -2yi

6 = -1-2y

Add 1 to each side

6+1 = -2y

7 = -2y

Divide by -2

7/-2 = y

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ZEFG and ZGFH are a linear pair, mZEFG = 3n+ 21, and mZGFH = 2n + 34. What are mZEFG and mZGFH?
marysya [2.9K]

Answer:

The answer is below

Step-by-step explanation:

∠EFG and ∠GFH are a linear pair, m∠EFG = 3n+ 21, and m∠GFH = 2n + 34. What are m∠EFG and m∠GFH?

Solution:

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m∠EFG = 3n + 21, m∠GFH = 2n + 34. Both angles form linear pairs, hence:

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