Remember this rhyme:
Hey Diddle Diddle, the medians the middle:
(Answer for your question: Median is 80%)
You add and divide for the Mean:
( Answer for your question: Mean is 93)
The mode is the one that appears the most:
( Answer for your question: Mode is 87%)
And the range is the difference between.:
( Answer for your question: Range is 54.)
I hope this helps! :)
We are asked in the problem to evaluate the integral of <span>(cosec^2 x-2005)÷cos^2005 x dx. The function is an example of a complex function with a degree that is greater than one and that uses special rules to integrate the function via the trigonometric functions. For example, we integrate
2005/cos^2005x dx which is equal to 2005 sec^2005 x since sec is the inverse of cos. The integral of this function when n >3 is equal to I=</span><span>∫<span>sec(n−2)</span>xdx+∫tanx<span>sec(n−3)</span>x(secxtanx)dx
Then,
</span><span>∫tanx<span>sec(<span>n−3)</span></span>x(secxtanx)dx=<span><span>tanx<span>sec(<span>n−2)</span></span>x/(</span><span>n−2)</span></span>−<span>1/(<span>n−2)I
we can then integrate the function by substituting n by 3.
On the first term csc^2 2005x / cos^2005 x we can use the trigonometric identity csc^2 x = 1 + cot^2 x to simplify the terms</span></span></span>
A^2 - b^2 = (a - b)(a + b)
169x^2 - 64 = (13x - 8)(13x + 8)
Answer:
backflip cartwheel
Step-by-step explanation:
Answer:
She will need more because that's not enough
Step-by-step explanation: