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seropon [69]
3 years ago
13

How many solutions does the system of equations below have?

Mathematics
1 answer:
denpristay [2]3 years ago
6 0

Answer:

There is one solution to this system of equations

Step-by-step explanation:

When solving, there is a specific point of intersection which is (7/6,-7/6), making the answer one solution.

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What is the slope of a line that is perpendicular to the line whose equation is 7x−3y=10?
Sonja [21]

Since this equation is already in standard form, there is no need to convert it. Standard form is Ax + By = C. In this equation, 7 = A, 3 = B, and 10 = C. From standard form, Ax + By = C equals negative A over B.

7x + 3y = 10

↓

\displaystyle\ m= \frac{-7}{-3}

Then you'd simplify.

\displaystyle\ m=\frac{7}{3}

The slope cannot be simplified any more, so this would be the final answer.

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<em>- Marlon Nunez</em>

7 0
3 years ago
436.8 divided by 62.08
Readme [11.4K]

Answer:

7.03 if your rounding to the nearest tenth then its 7

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The opposite of which number is closest to -5
Oliga [24]
The answer would be positive 5
8 0
2 years ago
Express 3/8 in thirty-seconds
Doss [256]
The answer is 12/32 i believe.
6 0
3 years ago
A^2(64a^2-3)/3=27-4a^2/4
frutty [35]
The answer is a = 3/4 = 0.75

First get rid of the paranthesis,
{a}^{2} (64 {a}^{2}  - 3) = 64 {a}^{4} -  3 {a}^{2}
Then set the denominators equal:
\frac{ 256 {a}^{4}  - 12 {a}^{2}}{12}  =  \frac{81 - 12 {a}^{2} }{12}
Then remove the denominators and solve:
256 {a}^{4}  - 12 {a}^{2}  = 81 - 12 {a}^{2}
Eliminate -12a^2 by adding 12a^2 to both sides:
256 {a}^{4}  = 81
Take the fourth root of them or take the square root twice:
\sqrt[4]{256 {a}^{4} }  =  \sqrt[4]{81}   \\  4a = 3
Divide both sides by 4:
a =  \frac{3}{4}  = 0.75
7 0
3 years ago
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