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ivann1987 [24]
3 years ago
15

What is the slope of a line that is perpendicular to the line whose equation is 7x−3y=10?

Mathematics
1 answer:
Sonja [21]3 years ago
7 0

Since this equation is already in standard form, there is no need to convert it. Standard form is Ax + By = C. In this equation, 7 = A, 3 = B, and 10 = C. From standard form, Ax + By = C equals negative A over B.

7x + 3y = 10

↓

\displaystyle\ m= \frac{-7}{-3}

Then you'd simplify.

\displaystyle\ m=\frac{7}{3}

The slope cannot be simplified any more, so this would be the final answer.

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<em>- Marlon Nunez</em>

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Unfortunately, I can't do it on a graph here, but I will do it algebraically.
The solution on the graph will be the point of intersection of the two lines representing the equations.
y + 2.3 = 0.45x . . . . . (1)
-2y = 4.2x - 7.8 . . . . . (2)
From (2), y = 3.9 - 2.1x
substituting for y in (1), we have:
3.9 - 2.1x + 2.3 = 0.45x
2.55x = 6.2
x = 6.2/2.55 = 2.4
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