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Evgesh-ka [11]
2 years ago
11

Ordena de menos a mayor las siguientes fracciones:

Mathematics
1 answer:
Ahat [919]2 years ago
3 0
7/12 , 2/3 , 3/4 , 5/6
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A survey was conducted at Giant Supermarket where 50 students were randomly chosen and asked
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Answer:

The answer for both apples and bananas is 21

The answer for only apples or only bananas is 45

Step-by-step explanation:

36 plus 30 minus 45

50-5 is 45

only apples or bananas is 15 + 9

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3 years ago
Two intersecting lines have ______ of point(s) in common.
Vladimir79 [104]
They only have 1 common point
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What is the following product?
Aneli [31]
Your correct it’s the first one
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A candle has been burning for 20 min and is now 25 cm tall. In an hour it will be 10 cm tall. Which equation models the height y
stiv31 [10]

Answer:

(y - 25) = - 0.25(x - 20)

Step-by-step explanation:

Given that :

Height of candle after burning for 20 minutes = 25 cm

Height after burning for 1 hr (60 minutes) = 10 cm

Height (y) in cm of candle x minutes after being lit:

Using the equation :

(y - y1) = m(x - x1)

m = (change in y / change in x)

Change in height within 60 minutes :

Height at 20 minutes = 25cm

Height after an hour = 10

Change in height per hour = (25 - 10) = 15cm

Hence, m = change in height per minute

15cm / 60 = 0.25cm ( - 0.25) (decrease in height)

y1 = 25 ; x1 = 20

(y - y1) = m(x - x1)

(y - 25) = - 0.25(x - 20)

4 0
2 years ago
A dairy farm uses the somatic cell count (SCC) report on the milk it provides to a processor as one way to monitor the health of
Eva8 [605]

Answer:

t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37  

p_v =P(t_{4}>2.37)=0.038  

If we compare the p value and a significance level assumed \alpha=0.1 we see that p_v so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.  

Step-by-step explanation:

Data given and notation

\bar X=250000 represent the sample mean  

s=37500 represent the standard deviation for the sample

n=5 sample size  

\mu_o =210250 represent the value that we want to test  

\alpha=0.1 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses to be tested  

We need to conduct a hypothesis in order to determine if the mean is higher than 210250, the system of hypothesis would be:  

Null hypothesis:\mu \leq 210250  

Alternative hypothesis:\mu > 210250  

Compute the test statistic  

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

We can replace in formula (1) the info given like this:  

t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37  

Now we need to find the degrees of freedom for the t distirbution given by:

df=n-1=5-1=4

Conclusion

Since is a one right tailed test the p value would be:  

p_v =P(t_{4}>2.37)=0.038  

If we compare the p value and a significance level assumed \alpha=0.1 we see that p_v so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.  

6 0
3 years ago
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