Answer:
0.8 or 80%
Step-by-step explanation:
Let A and B be the events
<em>A: “The concert goer went to Orlampa Skydome”
</em>
<em>B: “The concert goer went to the Bithlo Megaplax”
</em>
<em>
</em>Then the probability P(A) that a concert goer went to Orlampa Skydome is
<em>P(A) = 120/200 = 0.6
</em>
Similarly,
<em>
P(B) = 100/200 = 0.5
</em>
<em>
</em>We are looking for P(A∪B), the probability that a concert goer went to Orlampa Skydome OR the Bithlo Megaplax.
We know that
P(A∪B) = P(A) + P(B) - P(A∩B)
but P(A∩B) is the likelihood that a concert goer went to Orlampa Skydome AND the Bithlo Megaplax.
Since the events are independent,
<em>
P(A∩B) = P(A)P(B) = 0.6*0.5 = 0.3
</em>
and
P(A∪B) = 0.6 +0.5 - 0.3 = 0.8 or 80%
Answer: I think the answer is 80x + 60y < or equal to 1,000 (the first answer)
Step-by-step explanation:
because the person doesn't want to consume more than 1,000 mg
Answer:
<em>Good Luck!</em>
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Step-by-step explanation:
The width is ; (X-5)(x-6)
Sorry I don’t know the answer I am just answering to see something about my points because they are negative and I am trying something I am so sorry here is also a cute picture of Louis Tomlinson for you:)
