Answer:
0.8 or 80%
Step-by-step explanation:
Let A and B be the events
<em>A: “The concert goer went to Orlampa Skydome”
</em>
<em>B: “The concert goer went to the Bithlo Megaplax”
</em>
<em>
</em>Then the probability P(A) that a concert goer went to Orlampa Skydome is
<em>P(A) = 120/200 = 0.6
</em>
Similarly,
<em>
P(B) = 100/200 = 0.5
</em>
<em>
</em>We are looking for P(A∪B), the probability that a concert goer went to Orlampa Skydome OR the Bithlo Megaplax.
We know that
P(A∪B) = P(A) + P(B) - P(A∩B)
but P(A∩B) is the likelihood that a concert goer went to Orlampa Skydome AND the Bithlo Megaplax.
Since the events are independent,
<em>
P(A∩B) = P(A)P(B) = 0.6*0.5 = 0.3
</em>
and
P(A∪B) = 0.6 +0.5 - 0.3 = 0.8 or 80%