Answer:
109
Step-by-step explanation:
You can brute-force this:
Candidate numbers that are divisable by 13 if you take away 5: 18
, 31
, 44
, 57
, 70
, 83
, 96
, <u>109
</u>, 122
, 135
, 148
Candidate numbers that are divisable by 14 if you take away 11: 25
, 39
, 53
, 67
, 81
, 95
, <u>109
</u>, 123
, 137
Only 109 is in both lists.
Answer:
(3,7)
Step-by-step explanation:
The answer is 1. Because if u subtract 5-11 and 8-3 you would be left with 6 and 5 then subtract those and walla
31.875 as a improper fraction is ![\frac{255}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B255%7D%7B8%7D)
31.875 as a mixed fraction is ![31 \frac{7}{8}](https://tex.z-dn.net/?f=31%20%5Cfrac%7B7%7D%7B8%7D)
hope this helps!