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2 years ago

What is the area of a triangle that has a height of 8 feet and a base length of 5 feet? (1 point)

Mathematics

1 answer:

kvasek [131]2 years ago

8 0

Answer:

Area = 20 ft^2

Step-by-step explanation:

Triangle area is (1/2) Base x Height

Area = (1/2)(5)(8)

Area = 20 ft^2

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Find x<br> options;<br> a) 21√2/2<br> b) 21√2<br> c) 21√3/2<br> d) 7

pishuonlain [190]

The value of x is 21√2/2

The correct option is (A)

<h3>What is Trigonometry?</h3>

Trigonometry is a branch of mathematics that studies relationships between the sides and angles of triangles.

In triangle having angle 60.

sin 60 = P/ 7√3

√3/2= P/7√3

2P= 21

P= 21/2

Now again

cos 45= 21/2/x

1/√2 = 10.5/x

x= 21√2/2

Learn more about trigonometry here:

brainly.com/question/26719838

#SPJ1

6 0

2 years ago

7•7+3(4•4+3+2) what is the answer to this?????

sdas [7]

Answer:

Step-by-step explanation:

7x7 is 49+3=52(4x4=16+5=21 then you would do 52+21=73 and 3+2 is 5

7x7+3=52

4x4=16

3+2=5

16+5=21

52+21=73

73 is answer

5 0

3 years ago

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What must you do if the base is not a triangle or rectangle?

nikklg [1K]

Answer:

please write complete question

7 0

3 years ago

Circumference means all the way around the circle right

goblinko [34]

Answer:

yes circumference is all the way around a circle

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

PLease answer !!! Find constants $A$ and $B$ such that \[\frac{x + 7}{x^2 - x - 2} = \frac{A}{x - 2} + \frac{B}{x + 1}\] for all

Xelga [282]

Answer:

1. $(A,B) = (3,-2)$

2. The values of t are: -3, -1

Step-by-step explanation:

Given

$\frac{x + 7}{x^2 - x - 2} = \frac{A}{x - 2} + \frac{B}{x + 1}$

$|t| = 2t + 3$

Required

Solve for the unknown

Solving $\frac{x + 7}{x^2 - x - 2} = \frac{A}{x - 2} + \frac{B}{x + 1}$

Take LCM

$\frac{x + 7}{x^2 - x - 2} = \frac{A(x+1) + B(x-2)}{(x - 2)(x-1)}$

Expand the denominator

$\frac{x + 7}{x^2 - x - 2} = \frac{A(x+1) + B(x-2)}{x^2 - 2x + x -2}$

$\frac{x + 7}{x^2 - x - 2} = \frac{A(x+1) + B(x-2)}{x^2 - x -2}$

Both denominators are equal; So, they can cancel out

$x + 7 = A(x+1) + B(x-2)$

Expand the expression on the right hand side

$x + 7 = Ax + A + Bx - 2B$

Collect and Group Like Terms

$x + 7 = (Ax + Bx) + (A - 2B)$

$x + 7 = (A + B)x + (A - 2B)$

By Direct comparison of the left hand side with the right hand side

$(A + B)x = x$

$A - 2B = 7$

Divide both sides by x in $(A + B)x = x$

$A + B = 1$

Make A the subject of formula

$A = 1 - B$

Substitute 1 - B for A in $A - 2B = 7$

$1 - B - 2B = 7$

$1 - 3B = 7$

Subtract 1 from both sides

$1 - 1 - 3B = 7 - 1$

$-3B = 6$

Divide both sides by -3

$B = -2$

Substitute -2 for B in $A = 1 - B$

$A = 1 - (-2)$

$A = 1 + 2$

$A = 3$

Hence;

$(A,B) = (3,-2)$

Solving $|t| = 2t + 3$

Because we're dealing with an absolute function; the possible expressions that can be derived from the above expression are;

$t = 2t + 3$ and $-t = 2t + 3$

Solving $t = 2t + 3$

Make t the subject of formula

$t - 2t = 3$

$-t = 3$

Multiply both sides by -1

$t = -3$

Solving $-t = 2t + 3$

Make t the subject of formula

$-t - 2t = 3$

$-3t = 3$

Divide both sides by -3

$t = -1$

<em>Hence, the values of t are: -3, -1</em>

7 0

3 years ago

Read 2 more answers