For this problem, we are given a parallelogram with a diagonal drawn, inside it there are markings for a few angles. We need to determine the unknown angles.
Opposite sides of a parallelogram are parallel, this means we can treat the diagonal as a transversal line that crosses two parallel lines. Since this is the case, the angles 33º and xº are alternate interior angles and have the same length:
The opposite angles in a parallelogram are congruent, therefore:
The sum of internal angles is 360º, therefore we have:
The value of x is 33º, the value of y is 38º and the value of z is 109º.
X-7/5 = -2
x- 7 = -10
x = -3
The number is -3
Answer:
critical value = 5.29
Step-by-step explanation:
Given that they are divided into 4 groups and a sample of 5 test was selected
N = 5 * 4 = 20
k = 4
∝ = 0.01
Df for numerator ( SS group )= k - 1 = 3
Df for denominator ( SSE group ) = N - k = 20 - 4 = 16
DF ( degree of freedom )
Next we will use the F table to determine the critical value
Critical value = 
= 5.29
Hi!
For this equation, you can solve it by using the quadratic formula:
x=-b<span>±sqrt/b^2-4ab
-----------------------
2a</span>
The answer is C
1/2(5x + 12)
because the perimeter is equal 20x + 6
