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Dahasolnce [82]
3 years ago
10

Find an equation of the line passing through the point (6,2) and perpendicular to −2x−1y=−3

Mathematics
1 answer:
Maksim231197 [3]3 years ago
4 0
Answer: 
x = -1/2 y + 3/2
not 100% sure but hope i helped :) if not im srry :(
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Ben says the angle is an acute angle. Jeff says the angle is less than a straight angle. Explain whether their statements are co
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2 years ago
3a + 2b, when a = 10 and b= 5
tia_tia [17]

Answer:

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Slope-intercept form of the equation for the line?
vaieri [72.5K]

Answer:

\large\boxed{y=-\dfrac{3}{10}x+\dfrac{1}{2}}

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

m - slope

b - y-intercept

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points from the graph (-5, 2) and (5, -1).

Substitute:

m=\dfrac{-1-2}{5-(-5)}=\dfrac{-3}{10}=-\dfrac{3}{10}

We have the equation in form:

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Put the coordinates of the point (5, -1) to the equation:

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\dfrac{1}{2}=b\to b=\dfrac{1}{2}

4 0
3 years ago
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