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Dahasolnce [82]
3 years ago
10

Find an equation of the line passing through the point (6,2) and perpendicular to −2x−1y=−3

Mathematics
1 answer:
Maksim231197 [3]3 years ago
4 0
Answer: 
x = -1/2 y + 3/2
not 100% sure but hope i helped :) if not im srry :(
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Simplify ( -12) x ( 13) x (-15) <br><br> Please give explanation<br> fast please
kherson [118]

Answer:

2340

Step-by-step explanation:

(-12)×(13)×(-15)

=(-156)×(-15)[ (+) × (-) = (-)]

=2340[(-) × (-) = (+)]

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3 years ago
Match the area to each parallelogram and trapezoid.<br> brainliest
stealth61 [152]

Answer:

Area of first shape is 288ft^{2}, area of second shape is 45m^{2}, area of third shape is 34in^{2}.

Step-by-step explanation:

Area of first shape

A=bh

A=18*16

A=288

Second shape

A=bh

A=9*5

A=45

Third shape

A= 1/2 h(b1+b2)

A=1/24(12+5)

A=1/2*4(12+5)

A=1/2*4(17)

A=1/2*68

A=34

8 0
3 years ago
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This one is extremely confusing I’ve worked it out 6 times and still no answer can somebody plz help
vivado [14]
It should be A
Angle b=angle g
6x+8=4x+12
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6 0
3 years ago
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3x + y=11 <br> -2x + y=1 <br> Solve using substitution method
nata0808 [166]

Answer:

3x+yl=11

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y=11-3x

-2x+11-3x=11

-5x=11-11

so x=0

y=11-0

y=11

6 0
3 years ago
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Please help omg I don’t understand
In-s [12.5K]
The answer will be c
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