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Gennadij [26K]
2 years ago
8

What is the height of the triangle? 17 units 34 units 51 units 68 units

Mathematics
1 answer:
saveliy_v [14]2 years ago
6 0
51 units
Using right triangle formula we will get 51 explanation in the picture

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The lines on the graph below represent the cost of apples at four different stores.
Doss [256]
The cost of 10 apples would be 26 dollars because each pound is 14.
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A triangle has sides of lengths 9,7, and 12. Is it a right triangle? Explain.
Alex Ar [27]

Answer:

A triangle has sides of lengths 9,7, and 12 is not a right triangle .

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HELPPPP ASAP 1.Go to the website for the U.S. Bureau of Labor Statistics: www.bls.gov. Under the Subject Areas tab, look under P
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do you still need help for the answer?

Step-by-step explanation:

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3 years ago
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Can someone help me?
bixtya [17]

Answer:

y = 2.1x +5, 21 miles

Step-by-step explanation:

We will denote miles as "x"

Since she tipped the driver $5, that is a flat rate and that will be our y-intercept. Since it costs $2.10 per mile, we need to multiply that number by the number of miles

So our equation will be y = 2.1x +5

In order to figure out how many miles Ann lives from the airport, we need to substitute y for her grand total that she was charged

This gives us 49.10 = 2.10x + 5

First we need to subtract 5 from each side to get 44.10 = 2.10x

We then need to divide both sides by 2.10 to get 21 = x

Ann drove 21 miles

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3 years ago
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(5) Find the Laplace transform of the following time functions: (a) f(t) = 20.5 + 10t + t 2 + δ(t), where δ(t) is the unit impul
Aloiza [94]

Answer

(a) F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}

(b) F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}

Step-by-step explanation:

(a) f(t) = 20.5 + 10t + t^2 + δ(t)

where δ(t) = unit impulse function

The Laplace transform of function f(t) is given as:

F(s) = \int\limits^a_0 f(s)e^{-st} \, dt

where a = ∞

=>  F(s) = \int\limits^a_0 {(20.5 + 10t + t^2 + d(t))e^{-st} \, dt

where d(t) = δ(t)

=> F(s) = \int\limits^a_0 {(20.5e^{-st} + 10te^{-st} + t^2e^{-st} + d(t)e^{-st}) \, dt

Integrating, we have:

=> F(s) = (20.5\frac{e^{-st}}{s} - 10\frac{(t + 1)e^{-st}}{s^2} - \frac{(st(st + 2) + 2)e^{-st}}{s^3}  )\left \{ {{a} \atop {0}} \right.

Inputting the boundary conditions t = a = ∞, t = 0:

F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}

(b) f(t) = e^{-t} + 4e^{-4t} + te^{-3t}

The Laplace transform of function f(t) is given as:

F(s) = \int\limits^a_0 (e^{-t} + 4e^{-4t} + te^{-3t} )e^{-st} \, dt

F(s) = \int\limits^a_0 (e^{-t}e^{-st} + 4e^{-4t}e^{-st} + te^{-3t}e^{-st} ) \, dt

F(s) = \int\limits^a_0 (e^{-t(1 + s)} + 4e^{-t(4 + s)} + te^{-t(3 + s)} ) \, dt

Integrating, we have:

F(s) = [\frac{-e^{-(s + 1)t}} {s + 1} - \frac{4e^{-(s + 4)}}{s + 4} - \frac{(3(s + 1)t + 1)e^{-3(s + 1)t})}{9(s + 1)^2}] \left \{ {{a} \atop {0}} \right.

Inputting the boundary condition, t = a = ∞, t = 0:

F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}

3 0
3 years ago
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