Answer:
Set A's standard deviation is larger than Set B's
Step-by-step explanation:
Standard deviation is a measure of variation. One way to judge the value of standard deviation is by looking at the range of the data. In general, a dataset with a smaller range will have a smaller standard deviation.
The range of data Set A is 25-1 = 24.
The range of data Set B is 18-8 = 10.
Set A's range is larger, so we expect its standard deviation to be larger.
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The standard deviation is the root of the mean of the squares of the differences from the mean. In Set A, the differences are ±12, ±11, ±10. In Set B, the differences are ±5, ±3, ±1. We don't actually need to compute the RMS difference to see that it is larger for Set A.
Set A's standard deviation is larger than Set B's.
The equation given in the question is
13 + (w/7) = - 18
(91 + w) / 7 = - 18
91 + w = - 126
w = - 126 - 91
= - 217
I hope that the procedure is clear enough for you to understand. I also hope that this is the answer that you were looking for and the answer has actually come to your desired help.
Maybe u should do inverse operation on both sides idk but just try it
Answer:
Positive 37
Step-by-step explanation:
