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TiliK225 [7]
3 years ago
6

Maggie created this scale drawing of a soccer field, using a scale factor of 1 inch : 12 yards. She wants to make another scale

model of the same field, using a scale factor of 1 inch : 3 yards. Find the length and width of the new scale drawing.
Mathematics
1 answer:
larisa [96]3 years ago
7 0

The length and width of the new scale drawing is 36 inches and 24 inches respectively.

The given parameters:

  • <em>Original scale of the soccer field, 1 inch : 12 yards</em>

The original length and width of the soccer field is calculated as follows;

1 inch : 12 yards

  • original width = 6 x 12 yards = 72 yards
  • original length = 9 x 12 = 108 yards

For the new scale of 1 inch : 3 yards, the new length and width are represented as;

<em>the </em><em>new width</em><em>:</em>

\frac{1 \ inch}{x} = \frac{3 \ yards}{72 \ yards} \\\\x = 24 \ inches

<em>the </em><em>new length</em><em>:</em>

\frac{1 \ inch}{x} = \frac{3 \ yards}{108 \ yards} \\\\x = 36\ inches

Thus, the length and width of the new scale drawing is 36 inches and 24 inches respectively.

Learn more about scale drawing here:

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Which equation can be used to solve for x in the following diagram?
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∑ Hey, petalssquad10 ⊃

Answer:

( 10 x + 10 ) = 110

Step-by-step explanation:

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Hence, the equation we can be used to solve for x in the following diagram is:

( 10 x + 10 ) = 110

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6 0
2 years ago
Please help me <br><br> Solve the right triangle. Round to the nearest tenth, if necessary.
Darya [45]

Answer:

<em>c</em> = 32.1

<em>b = </em>34.4

<em />m\angle{B}= 47 degrees

Step-by-step explanation:

Using sine = opp/hyp. to find side c:

sin(43)=\frac{c}{47}=32.05392...

Using cosine = adj/hyp. to find side b:

cos(43)=\frac{b}{47}=34.37362...

Finding angle B:

It's a right triangle and you're given one of the acute angles, which means you can find the missing third angle. All triangles interior angles add to equal 180 degrees.

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First-order linear differential equations
kkurt [141]

Answer:

(1)\ logy\ =\ -sint\ +\ c

(2)\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c

Step-by-step explanation:

1. Given differential equation is

  \dfrac{dy}{dt}+ycost = 0

=>\ \dfrac{dy}{dt}\ =\ -ycost

=>\ \dfrac{dy}{y}\ =\ -cost dt

On integrating both sides, we will have

  \int{\dfrac{dy}{y}}\ =\ \int{-cost\ dt}

=>\ logy\ =\ -sint\ +\ c

Hence, the solution of given differential equation can be given by

logy\ =\ -sint\ +\ c.

2. Given differential equation,

    \dfrac{dy}{dt}\ -\ 2ty\ =\ t

=>\ \dfrac{dy}{dt}\ =\ t\ +\ 2ty

=>\ \dfrac{dy}{dt}\ =\ 2t(y+\dfrac{1}{2})

=>\ \dfrac{dy}{(y+\dfrac{1}{2})}\ =\ 2t dt

On integrating both sides, we will have

   \int{\dfrac{dy}{(y+\dfrac{1}{2})}}\ =\ \int{2t dt}

=>\ log(y+\dfrac{1}{2})\ =\ 2.\dfrac{t^2}{2}\ + c

=>\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c

Hence, the solution of given differential equation is

log(y+\dfrac{1}{2})\ =\ t^2\ +\ c

8 0
4 years ago
3x^2+5x+25, when x=3
Vaselesa [24]

[ Answer ]

\boxed{121}

[ Explanation ]

3x^{2} + 5x + 25

X = 3

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Solve

5 * 3 = 15

3 * 3 = 9

9 * 9 = 81

Insert Numbers

81 + 15 + 25

= 121

\boxed{[ \ Eclipsed \ ]}

8 0
4 years ago
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