We can find this out by using the parameter equation for a circle
r = radius = 11
p = 69.115
If we round
p = 69.12
Answer:
We start with the equation:
(x^2 - 1)/(x + 1) = 2
We want to rewrite this in standard form.
We can multiply both sides by (x + 1) to get:
((x^2 - 1)/(x + 1))*(x + 1) = 2*(x + 1)
x^2 - 1 = 2*(x + 1) = 2*x + 2
Now we can move all the terms to one side to get:
x^2 - 1 - 2 - 2*x = 0
x^2 - 2*x - 3 = 0
And this is a standard quadratic equation, that we can solve by using the Bhaskara's formula, this will give us the solutions:
Then the two solutions are:
x = (2 + 4)/2 = 3
x = (2 - 4)/2 = -1
Answer:
Where's the Answer? There's No
Answer:
B. 3≤x≤ 6
Step-by-step explanation:
When a question asks for the domain of a function, it is asking for <u>all possible x-values</u>. Look at the graph of the function- there are no points on the graph where x=1, so we know that C and D are definitely wrong since they include 1. The two that are left look very similar, but A means "3 is greater than or equal to x, x is greater than or equal to 6." This has to be wrong because it says that 3 is greater than 6, which is obviously incorrect. The only answer left is B, which is correct because it includes all possible x-values.
lmk if this is incorrect or hard to understand, hope this helps!!!
(btw dont click on unknown links like the one in the other answer)