All categories

3 years ago

Need the answer to this question

Mathematics

1 answer:

Ipatiy [6.2K]3 years ago

3 0

Answer:

3 Rd one I think, it's correct

You might be interested in

Express the inequality a>−3.3 in interval notation

iren [92.7K]

Answer:

(-3.3,∞)

Step-by-step explanation:

a will be greater than -3.3

4 0

3 years ago

What are the original substances called in a chemical reaction?

yulyashka [42]

Answer:

reactants

A chemical reaction is the process in which atoms present in the starting substances rearrange to give new chemical combinations present in the substances formed by the reaction. These starting substances of a chemical reaction are called the reactants, and the new substances that result are called the products.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Dia loves to drink hot chocolate in the morning. Her dad makes the hot chocolate the same way each day. He uses 3 ounces of choc

Mashutka [201]

Answer:

Step-by-step explanation:

5+3=8

5 0

3 years ago

Read 2 more answers

Solve the initial value problem

tigry1 [53]

$9(t+1)\dfrac{\mathrm dy}{\mathrm dt}-7y=14t\implies\dfrac{\mathrm dy}{\mathrm dt}-\dfrac7{9(t+1)}y=\dfrac{14t}{9(t+1)}$

Look for an integrating factor $\mu(t)$ :

$\ln\mu=\displaystyle-\frac79\int\frac{\mathrm dt}{t+1}=-\frac79\ln(t+1)\implies\mu=(t+1)^{-7/9}$

Multiply both sides by $\mu$ :

$(t+1)^{-7/9}\dfrac{\mathrm dy}{\mathrm dt}-\dfrac79(t+1)^{-16/9}y=\dfrac{14}9t(t+1)^{-16/9}$

Condense the left side as the derivative of a product:

$\dfrac{\mathrm d}{\mathrm dt}\left[(t+1)^{-7/9}y\right]=\dfrac{14}9t(t+1)^{-16/9}$

Integrate both sides:

$(t+1)^{-7/9}y=\displaystyle\frac{14}9\int t(t+1)^{-16/9}\,\mathrm dt$

For the integral on the right, substitute

$u=t+1\implies t=u-1\implies\mathrm dt=\mathrm du$

$\displaystyle\int t(t+1)^{-16/9}\,\mathrm dt=\int(u-1)u^{-16/9}\,\mathrm du$

$\displaystyle=\int\left(u^{-7/9}-u^{-16/9}\right)\,\mathrm du=\frac92u^{2/9}+\frac97u^{-7/9}+C$

$\implies(t+1)^{-7/9}y=\dfrac{14}9\left(\dfrac92(t+1)^{2/9}+\dfrac97(t+1)^{-7/9}+C\right)$

$\implies(t+1)^{-7/9}y=7(t+1)^{2/9}+2(t+1)^{-7/9}+C$

$\implies y=7(t+1)+2+C(t+1)^{7/9}=7t+9+C(t+1)^{7/9}$

Given that $y(0)=12$ , we get

$12=9+C\implies C=3$

$\implies\boxed{y(t)=7t+9+3(t+1)^{7/9}}$

6 0

3 years ago

What is the slope of the line through the points (–3, 5) and (4, 5)?

kicyunya [14]

The slope is 0.
Using the formula (y2-y1) / (x2-x1), we wee that when subtracting y2 from y1 we get zero in the numerator and 7 in the denominator.

0/7 = 0

Another way to determine this is by plotting the two points and seeing that they form a horizontal line, indicating that there is a slope of 0.

6 0

3 years ago