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CaHeK987 [17]
3 years ago
12

luis spent 8.75 on snacks at a basketball game. candy costs 1.25$ per package and chips cost .50$. Luis bought 10 snacks how man

y of each snack did he buy?
Mathematics
1 answer:
ale4655 [162]3 years ago
5 0

Answer:

Luis bought 5 packages of candy and 5 bags of chips

Step-by-step explanation:

1.25 for candy

0.50 for chips

1.25c + 0.50c = 8.75

First I tried to see how many times I could multiply 1.25, the answer that made the most sense was 5 because not only is 5 + 5 = 10, but when it equals the amount of money. So I changed my equation:

1.25(5) + 0.5(5)

6.25 + 2.5 = 8.75

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FRUIT
laiz [17]
2p+6a=$14
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3p+9a=21
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3p=21-9a
divide all by 3
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2(7-3a)+6a=14
14-6a....+6a=14

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5 0
3 years ago
Eliza is two years younger than half her brother, Juan’s age. Write an equation to represent Eliza’s age. If Juan is 6 how old i
Natalka [10]
X = Juan's age
y = Eliza's age

Some key words/phrases we can use to help us make the equation are:

-is (whatever comes after this word usually equals the end result, or what it equals)
-two years younger
-than
-half her brother's age
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just break it down :)

x/2 (half her brother's age) - 2 (two years younger) = y (Eliza is...)

| basically,
v

x/2 - 2 = y
So if Juan is 6, then we need to plug in 6 for x.

6/2 - 2 = y

3 - 2 = y

1 = y

ANSWER: Eliza is one year old.
6 0
3 years ago
X-1=y what is the answer plz give me the answer
guajiro [1.7K]

Answer:

<h2>X = 0</h2><h2>Y = 1</h2>

First of all, observe that this is a line, since you can rewrite the equation as y−x+1=0 , which follows the pattern of the generic line ax+by+c=0 .

To draw a line you need two of its points, which you can connect.

To find two points, you can plug any value for one variable, and solve for the other.

For example, let's choose

x=0 . The equation becomes

0−1=y , and so y=−1 .

The first point is thus (0,−1).

Then, let's choose

x=1 . The equation becomes 1−1=y , and so y=0 . The first point is thus

(1,0).

Now you only need to draw the points

(0,−1)

Step-by-step explanation:

Hope it is helpful...

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