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qwelly [4]
2 years ago
8

Solve for the value of x:-

" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
enot [183]2 years ago
5 0

4x-5 = 3

4x = 8

x = 8÷4

x = 2

Oksi-84 [34.3K]2 years ago
4 0

\qquad\qquad\huge\underline{{\sf Answer}}

\large \textbf{Let's evaluate~}

  • \textsf{4x - 5 = 3}

  • \textsf{4x = 5 + 3}

  • \textsf{4x = 8}

  • \textsf{x = 8 ÷ 4}

  • \textsf{x = 2}
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<span>Hi

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sveticcg [70]

(a)The domain of the function is, \rm x \geq -c^2 \ x\neq0

(b)The given function is discontinuous at x=0.

<h3>What is the domain and range of a function?</h3>

Domain is the set of values for which the given function is defined. Range is the set of all values which the given function can output.

The standard function is;

\rm f(x)= \frac{\sqrt{x+c^2-c} }{x}  , c > 0

The domain of the given function is found as;

\rm  x+c^2 \geq 0 \  x\neq 0 \\\\ x\geq-c^2 \ x\neq 0

The domain of the function is,

\rm x \geq -c^2 \ x\neq0

To find the function is continuous or not, we have to find the continuity;

\rm f(x) = \frac{\sqrt{ x+c^2-c}}{x} ,c > 0

At x= 0 the function is undefined. So that the function is discontinuous at x=0.

Hence, The domain of the function is, \rm x \geq -c^2 \ x\neq0 and the function is discontinuous at x=0.

To learn more about domain, refer to the link:

brainly.com/question/20073127

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The polar equation is r = 2 + cos(theta).

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A choir is performing in front of an audience. a microphone is placed in front of the choir to capture sound.

The polar equation represents the microphone the choir is using i.e

On edge i.e r = 2 + cos(theta)

Hence, The polar equation is r = 2 + cos(theta).

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