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3 years ago

9

A Karen's car is shown below.Which is closest to the distance traveled, in feet, after 3 full rotations of the tire? use pi = 22

/7.

2 answers:

iren2701 [21]3 years ago

7 0

Answer: This is approximately 3.14

lianna [129]3 years ago

7 0

Awnser this is aprox 3.14

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If h(x) = x – 7 and g(x) = x2, which expression is equivalent (g o h)(5)

Zanzabum

(goh)(x) = (g(x))(h(x)) = (x^2)(x-7) = x^3 -7x^2
then (goh)(5) = (5^3)-7(5)^2 = 124-7(25) = 124-175 = -51

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3 years ago

Traveling at a average speed of 50 miles per hour the trip from point a to be is 2 hours traveling at a speed of 20 miles per ho

dem82 [27]

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You invest $1,100 in an account that has an annual interest rate of 2.1%, compounded continuously. How much money will be in the

uranmaximum [27]

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3 years ago

A 4-lb. force acting in the direction of (vector) 4,-2 moves an object just over 7ft from point (0,4) to (5,-1). Find the work d

Tcecarenko [31]

To solve this problem, we have to find the net displacement and the net force and the multiply the dot product together and get the work done.

The work done on moving the object is 27ft*lbs

<h3>Work done in moving the object from point A to point B</h3>

To find the work done on this object, let's find the net force on the object.

Data;

force = 4lb
direction = 4, -2
displacement = 7ft
direction = (0, 4) to (5,1)

The unit vector of the force is

$\sqrt{4^2 +(-2)^2} =\sqrt{16 + 4} = \sqrt{20}$

$\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} }$

The net force acting on the object is

$F = 4(\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} })\\F= (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } )$

The displacement on the object is 7ft through (0,4) to (5, -1)

The unit vector on displacement is

$\sqrt{5^2 + (-1-4)^2} = \sqrt{25+25} = \sqrt{50}$

$\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }$

The net displacement will be

$7(\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }) = \frac{35}{\sqrt{50} }, \frac{-35}{50}$

The work done will be F.d

$w = f. d \\$

$w = (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } ) * \frac{35}{\sqrt{50} }, \frac{-35}{50}\\w = 17.71+ 8.854\\w = 26.567 = 27ft*lbs$

The work done on moving the object is 27ft*lbs

Learn more on work done on an object here;

brainly.com/question/26152883

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2 years ago

In a class election Mark received 3/5 of the votes in his class of 30 students

Andrei [34K]

So, we need to find how many students voted for Mark, I assume.

So, we need to divide 30 by 5

30 ÷ 5 = 6

So, 3 × 6 =18.

So, Mark received 18 votes

I think this is the answer.

Glad I could help, and good luck!

AnonymousGiantsFan

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3 years ago

Read 2 more answers