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2 years ago

Calculate the exact value of cos(a−b) given that sin a=12/13 with π/2

Mathematics

1 answer:

Lady bird [3.3K]2 years ago

8 0

Answer:

Step-by-step explanation:

$sin ~a=\frac{12}{13} ,\frac{\pi}{2}$

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Archy [21]

Answer:

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Step-by-step explanation:

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3 years ago

If the outliers are not included, what is the mean of the data set?

ioda

If you don't include the outlier (50) then it is 79.7

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2 years ago

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Verify sin4 x- sin2x = cos4x – cos2x is an identity

Andrej [43]

Step-by-step explanation:

sin⁴ x − sin² x

Factor:

(sin² x) (sin² x − 1)

Pythagorean identity:

(1 − cos² x) (-cos² x)

Distribute:

-cos² x + cos⁴ x

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3 years ago

Casey wants to buy a gym membership. One gym has a $70 joining fee and cost $35 per month. Another Jim has no joining fee and co

irga5000 [103]

Answer:

same amount at 2 months. he'd pay 140.

Step-by-step explanation:

35(month) +35(month) =70(joining fee). 70+70=140. that's two months at the first gym.

the second gym is also 140 for the two months because each month is $70. and 70+70=140

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3 years ago

A circle with radius of 5 cm sits inside a 11 cm * 11 cm rectangle.

Nadusha1986 [10]

Answer:

42.43 $cm^{2}$

Step-by-step explanation:

Given:

A circle with a radius of 5 cm sits inside a 11 cm x 11 cm rectangle.

Question asked:

What is the area of the shaded region as shown in the figure ?

Solution:

First of all calculate area of circle and then area of rectangle:-

$Area\ of\ cirle=\pi r^{2}$

$=\frac{22}{7} \times5\times5\\ \\ =\frac{550}{7}\\ \\=78.571\ cm^{2}\\$

<u>As here length an width both are 11 cm, we can say that this is a square.</u>

<u /> $Area\ of\ square=(Side)^{2}$

$=11\times11=121\ cm^{2}$

Now, area of shaded region = Area of square - Area of circle

= 121 - 78.571 = 42.429 $cm^{2}$

Therefore, the area of the shaded region will be 42.43 $cm^{2}$

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5 0

3 years ago