Answer:
The area of the square adjacent to the third side of the triangle is 11 units²
Step-by-step explanation:
We are given the area of two squares, one being 33 units² the other 44 units². A square is present with all sides being equal, and hence the length of the square present with an area of 33 units² say, should be x² = 33 - if x = the length of one side. Let's make it so that this side belongs to the side of the triangle, to our convenience,
x² = 33,
x = 
.... this is the length of the square, but also a leg of the triangle. Let's calculate the length of the square present with an area of 44 units². This would also be the hypotenuse of the triangle.
x² = 44,
x = 
.... applying pythagorean theorem we should receive the length of a side of the unknown square area. By taking this length to the power of two, we can calculate the square's area, and hence get our solution.
Let x = the length of the side of the unknown square's area -
= 
+ 
,
x = 
... And squared is 11, making the area of this square 11 units².
Answer:
45/4 7/2 9/2
Step-by-step explanation:
I'm not sure if this is what you wanted so if its not sorry.
The fraction of students having cupcakes with chocolate frosting is 
<u>Explanation:</u>
Given:
Let the number of students in class be x
According to the question:
Students having cupcake = 
Frosting cupcakes = 
Fraction of students having cupcakes with chocolate frosting =
= 
Thus, the fraction of students having cupcakes with chocolate frosting is
First term of sequence is found by letting n=1. Then a_1 = 1/2.
Each new term is equal to the previous one times (4/3). We call (4/3) the "common ratio."
