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2 years ago

Why does the graph of a function shift left when K is positive and to the right when K is negative?

Mathematics

1 answer:

Sedaia [141]2 years ago

3 0

Answer:

You can visualize this easily.

y=f(x+h)

Now if the argument of the function is taken as (x−h) the value of y will be f((x−h)+h)=f(x)

The function y acquires the value of f(x) at (x−h) amounting to a left shift.

Hope this makes things clear.

Step-by-step explanation:

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Find the domain and range of the function:<br> f(t)=sec[((pi)t)/4]

beks73 [17]

The domain and range of the function f(t)=sec[((pi)t)/4] are the following:

<span>Domain: All the real numbers except t = 2 + 4k, where k is an integer. </span>

Range: (-∞, -1] U [1, ∞)

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3 years ago

The area in square feet, inside a rectangle is given by the expression 1600 x? What is the value

Juli2301 [7.4K]

Answer:1375

Step-by-step explanation:

X= 15 is given

X squared is 15x15 = 225

1600 - 225= 1375

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2 years ago

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3 years ago

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3 years ago

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If Diana walks forward and her angle looking to the top of the building changes to 40°, how much closer is she to the building?

elena55 [62]

The closer Diana gets to the building, the smaller the angle becomes

Diana is 17.6 feet closer to the building

<h3>How to calculate the distance from the building</h3>

To calculate the distance between her and the building, we make use of the following tangent ratio

$\tan(\theta) = \frac{h}{d}$

Where:

$\theta = 40^o$
h represents the height of the building; h = 130
d represents the distance from the building

So, we have:

$\tan(40) = \frac{130}{d}$

Make d the subject

$d = \frac{130}{\tan(40)}$

Evaluate tan(40)

$d = \frac{130}{0.8391}$

$d = 154.93$

Initially, Diana is at a distance of 172.53.

The difference in both distance is:

$\Delta d = 172.53 - 154.93$

$\Delta d = 17.6$

Hence, Diana is 17.6 feet closer to the building

Read more about trigonometry ratios at:

brainly.com/question/4326804

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2 years ago