Answer:
f(x) = x^2 + 2x - 3 and g(x) = x^2 - 9
(f/g)(x) = (x^2+ 2x -3) / (x^2 - 9)
(f/g)(x) = (x +3 )(x - 1) / (x + 3)(x - 3)
(f/g)(x) = (x - 1) / (x - 3)
So
(f/g)(4) = (4 - 1)/(4 -3)
(f/g)(4) =3/1
(f/g)(4) = 3
(f+g)(x) = x^2+ 2x - 3 + x^2 - 9
(f+g)(x) = 2x^2 + 2x - 12
(f+g)(x) = 2(4)^2 + 2(4) - 12
(f+g)(4) = 32 + 8 - 12
(f+g)(4) = 28
Step-by-step explanation:
the answer is B y=[x+10]-3
100, 105, 110, 115, 120, 125, 130, 135, 140, 145, 150,...
Using it's concept, it is found that the relative frequency of 6th graders who rode a car is given by:
D. 55%.
<h3>What is a probability?</h3>
A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.
The number of 6th graders is given by:
N6 = 576 - (219 + 189) = 168.
The number of 6th graders who rode a car is:
N6C = 168 - 75 = 93
Hence the relative frequency is given by:
r = 93/168 = 55%.
Hence option D is correct.
More can be learned about relative frequencies at brainly.com/question/14398287
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Answer:
$72500
Step-by-step explanation:
$72500
