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yarga [219]
3 years ago
11

18 Enter as a mixed number. 8

Mathematics
2 answers:
larisa [96]3 years ago
4 0

Answer:

2 2/8

Step-by-step explanation:

8 can go into 18 two times, and 2 is left over

I hope this helps! Have a great day!

Fofino [41]3 years ago
3 0

Answer:

2 1/4

Step-by-step explanation:

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Coordinate Geometry Use the graph. Write each
mestny [16]

33) AC=6 and BD=6, so AC/BD=1

34) By the distance formula,

AE=\sqrt{(-2-4)^2 + (8-0)^2 }=10\\

Also, EC = 8. So, AE/EC = 5/4.

35) \frac{8-0}{4-2}=4

36) \frac{8-0}{4-8}=-2

4 0
2 years ago
a culture started with 2000 bacteria after 6 hours it grew to 2400 bacteria how many bacteria will grow after 16 hours
Monica [59]
Started at 2000....after 6 hrs it grew to 2400...that means in 6 hrs, it grew 400.
6/400 = 16/x ....6 hrs to 400 = 16 hrs to x
this is a proportion, so we cross multiply
(6)(x) = (400)(16)
6x = 6400
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6 0
4 years ago
Read 2 more answers
100 textbooks increased by 99%
Gala2k [10]
<span>100 textbooks increased by 99%

Do this:

First, make 99% a decimal, to do this, you must divide 99 by 100

you get 0.99

multiply 0.99 by 100

you get 99

then, add 99 to 100 and you get 199

so the total sum is 199!!


Hope this helped!
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5 0
3 years ago
PLEASE HELP ME FAST!!!!! LOTS OF POINTS
Andrej [43]

Answer:

its b

Step-by-step explanation:

4 0
3 years ago
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A clinical trial was conducted to test the effectiveness of the drug zopiclone for treating insomnia in older subjects. Before t
aleksklad [387]

Answer:

We cannot say that the mean wake time are different before and after the treatment, with 98% certainty. So the zopiclone doesn't appear to be effective.

Step-by-step explanation:

The goal of this analysis is to determine if the mean wake time before the treatment is statistically significant. The question informed us the mean wake time before and after the treatment, the number of subjects and the standard deviation of the sample after treatment. So using the formula, we can calculate the confidence interval as following:

IC[\mu ; 98\%] = \overline{y} \pm t_{0.99,n-1}\sqrt{\frac{Var(y)}{n}}

Knowing that t_{0.99,15} = 2.602:

IC[\mu ; 98\%] = 98.9 \pm 2.602\frac{42.3}{4} \Rightarrow 98.9 \pm 27.516

IC[\mu ; 98\%] = [71.387 ; 126,416]

Note that 102.8 \in [71.384 ; 126.416] so we cannot say, with 98% confidence, that the mean wake time before treatment is different than the mean wake time after treatment. So the zopiclone doesn't appear to be effective.

7 0
3 years ago
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