The bisector of angle APQ passes through O and this is illustrated below.
<h3>How to illustrate the information?</h3>
From the information given, the center is O. and the circle passes through O and cuts at K.
In this case, it should be noted that the circles are equal according to the SAS test.
Here, AOB + APQ = 180° (Linear pair)
2AOB = 180
AOB = 90.
Therefore, the bisector of angle APQ passes through O.
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Answer:
second option
Step-by-step explanation:
Given the rule
(x, y ) → (x + 3, y - 5)
This means add 3 to the original x- coordinate and subtract 5 from the original y- coordinate, that is
D(4, - 4 ) → D'(4 + 3, - 4 - 5 ) → D'(7, - 9 )
E(5, - 5 ) → E'(5 + 3, - 5 - 5 ) → E'(8, - 10 )
Answer:
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Step-by-step explanation:
Given
The attached graph
Required
Determine the solution
The solution here is the intersection points of the two lines. From the attachment, both lines meet


<em>Hence, the solution is: </em>
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Answer:
(x - 2)(x² + 2x + 4)
Step-by-step explanation:
A difference of cubes factors in general as
• a³ - b³ = (a - b)(a² + ab + b² )
note 8 = 2³ = 8 ⇒ b = 2 , with a = x
Hence
x³ - 8
= x³ - 2³
= (x - 2)(x² + 2x + 2²) = (x - 2)(x² + 2x + 4)