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Art [367]
2 years ago
11

A diver begins at sea level and dives down 200 feet. He ascends at a steady rate of 12 and one-third feet per minute for 4. 5 mi

nutes. Which of the following numerical expressions represents the final depth of the diver? 200 12 and one-third(4. 5) 200 – 12 and one-third(4. 5) –200 12 and one-third(4. 5) –200 – 12 and one-third(4. 5).
Mathematics
1 answer:
dexar [7]2 years ago
6 0

The diver's depth is 55.485 feet.

Option B represents the correct expression of the equation.

<h2>How do you express the given condition in an equation form?</h2>

Given that the total depth is 200 feet. the steady rate of the diver is 12 and one-third feet per minute. The total time taken by the diver is 4.5 minutes.

The above condition can be written in equation form is given below.

Total Depth = Steady Rate per Minute \times Total Time

200 = (12+\dfrac {1}{3}) \times 4.5

200 - ((12+\dfrac{1}{3}) \times 4.5) = 0

Hence we can conclude that option B represents the correct form of the equation.

To know more, follow the link given below.

brainly.com/question/7161930.

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Ezra measured a swimming pool and made a scale drawing. He used the scale 9 millimeters = 1 meter. What is the scale factor of t
mr Goodwill [35]
1mm = .11m

You can get this by simplifying the numbers you already have
6 0
3 years ago
50× 3/8 how to reduce answer to lowest te
hoa [83]

The lowest term is \frac{75}{4}.

Solution:

Given expression is 50\times\frac{3}{8}

<u>To reduce this term to the lowest term:</u>

$50\times\frac{3}{8}=\frac{50}{1}\times\frac{3}{8}

Multiply the numerator and denominator.

$50\times\frac{3}{8}=\frac{150}{8}

Now, divide the numerator and denominator by the greatest common factor.

Here 150 and 8 both have common factor 2.

So, divide numerator and denominator by 2.

           $=\frac{150\div2}{8\div2}

           $=\frac{75}{4}

$50\times\frac{3}{8}=\frac{75}{4}

Hence the lowest term is \frac{75}{4}.

4 0
3 years ago
Can someone help me with this please? Thank you!
Finger [1]

Answer:

528 cm²

Step-by-step explanation:

First I would calculate the area of the side rectangles:

20 x 9 = 180 cm²

There are two identical rectangles on both sides so i would x2

180 x 2 = 360 cm²

The area of the middle rectangle:

6 x 20 = 120 cm²

The area of the triangles:

Area of a triangle = (Base x Height)/2

8 x 6 = 48

48 ÷ 2 = 24

There are two identical triangles on the bottom and the top so x2

24 x 2 = 48

Now add all the values up:

360 + 120 + 48 = 528 cm²

I hope this helps!

5 0
2 years ago
Verify that 2,-1 and 1⁄2 are the zeroes of the cubic polynomial
Mariulka [41]

Answer:

i) Since P(2), P(-1) and P(½) gives 0, then it's true that 2,-1 and 1⁄2 are the zeroes of the cubic polynomial.

ii) - the sum of the zeros and the corresponding coefficients are the same

-the Sum of the products of roots where 2 are taken at the same time is same as the corresponding coefficient.

-the product of the zeros of the polynomial is same as the corresponding coefficient

Step-by-step explanation:

We are given the cubic polynomial;

p(x) = 2x³ - 3x² - 3x + 2

For us to verify that 2,-1 and 1⁄2 are the zeroes of the cubic polynomial, we will plug them into the equation and they must give a value of zero.

Thus;

P(2) = 2(2)³ - 3(2)² - 3(2) + 2 = 16 - 12 - 6 + 2 = 0

P(-1) = 2(-1)³ - 3(-1)² - 3(-1) + 2 = -2 - 3 + 3 + 2 = 0

P(½) = 2(½)³ - 3(½)² - 3(½) + 2 = ¼ - ¾ - 3/2 + 2 = -½ + ½ = 0

Since, P(2), P(-1) and P(½) gives 0,then it's true that 2,-1 and 1⁄2 are the zeroes of the cubic polynomial.

Now, let's verify the relationship between the zeros and the coefficients.

Let the zeros be as follows;

α = 2

β = -1

γ = ½

The coefficients are;

a = 2

b = -3

c = -3

d = 2

So, the relationships are;

α + β + γ = -b/a

αβ + βγ + γα = c/a

αβγ = -d/a

Thus,

First relationship α + β + γ = -b/a gives;

2 - 1 + ½ = -(-3/2)

1½ = 3/2

3/2 = 3/2

LHS = RHS; So, the sum of the zeros and the coefficients are the same

For the second relationship, αβ + βγ + γα = c/a it gives;

2(-1) + (-1)(½) + (½)(2) = -3/2

-2 - 1½ + 1 = -3/2

-1½ - 1½ = -3/2

-3/2 = - 3/2

LHS = RHS, so the Sum of the products of roots where 2 are taken at the same time is same as the coefficient

For the third relationship, αβγ = -d/a gives;

2 * -1 * ½ = -2/2

-1 = - 1

LHS = RHS, so the product of the zeros(roots) is same as the corresponding coefficient

7 0
3 years ago
Please help me on this!
Tanya [424]
Answer: A. 4.
Explanation: solving graphically
6 0
1 year ago
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