Answer:
13. x = 52.8°
14. 663.65 ft
15. 30.7 ft
Step-by-step explanation:
The mnemonic SOH CAH TOA is intended to remind you of the relations between sides of a right triangle and trig functions of the acute angles.
__
<h3>13.</h3>
The sides adjacent and opposite the angle are marked. The relevant trig relation is ...
Tan = Opposite/Adjacent
tan(x°) = 2.5/1.9
The angle is found using the inverse tangent function:
x° = arctan(2.5/1.9) ≈ 52.8°
__
<h3>14.</h3>
Again, the tangent relation comes into play. The given values are the side opposite and the angle, and we are asked for the side adjacent.
Tan = Opposite/Adjacent
tan(11°) = (129 ft)/(distance to shore)
distance to shore = (129 ft)/tan(11°)
distance to shore ≈ 663.65 ft
__
<h3>15.</h3>
In this scenario, the given angle is opposite the given side of the triangle. The measure of the hypotenuse is needed.
Sin = Opposite/Hypotenuse
sin(71°) = (29 ft)/(ladder length) . . . . substitute given information
ladder length = (29 ft)/sin(71°) . . . . . . solve for ladder length
ladder length ≈ 30.7 ft
Answer:
![\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%267%5C%5C5%26-8%5C%5C3%26-9%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dc%5C%5Cd%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-16%5C%5C3%5C%5C-15%5Cend%7Barray%7D%5Cright%5D)
This tells us that:
![A=\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%267%5C%5C5%26-8%5C%5C3%26-9%5Cend%7Barray%7D%5Cright%5D)
![b=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]](https://tex.z-dn.net/?f=b%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-16%5C%5C3%5C%5C-15%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
So we are saying we have scalars, c and d, such that:
![c\left[\begin{array}{ccc}5\\5\\ 3\end{array}\right]+d\left[\begin{array}{ccc}7\\-8\\-9\end{array}\right]=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]](https://tex.z-dn.net/?f=c%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%5C%5C5%5C%5C%203%5Cend%7Barray%7D%5Cright%5D%2Bd%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%5C%5C-8%5C%5C-9%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-16%5C%5C3%5C%5C-15%5Cend%7Barray%7D%5Cright%5D)
.
So we want to find a way to express this as:
Ax=b where x is the scalar vector, ![\left[\begin{array}{ccc}c\\d\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dc%5C%5Cd%5Cend%7Barray%7D%5Cright%5D)
.
So we can write this as:
Answer:
each side is 31cm
Step-by-step explanation:
91/3=31
31+31+31=93
You combine the like terms to get
2s^2y^2-4a^2sy+2a^4
Answer:
2/5
Step-by-step explanation:
I found two point and counted the Y change and the X change. Rise over run.
