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KengaRu [80]
2 years ago
9

Which function describes the arithmetic sequence shown -5,-7,-9,-11,-13

Mathematics
1 answer:
oksano4ka [1.4K]2 years ago
4 0

Answer:

n(x)=x-2

Step-by-step explanation:

You can notice that between each of the arithmetic sequence there is a addition of 2. So we know that to add a 2 to get the next value. We can write it as n(x) where n is a function where x is the number:

  • n is the function and x repersent the number which is given
  • We can write this function as: n(x)=x-2
  • So if we input x = -5 we will get -7. If we input -11 we get -13.

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lidiya [134]
D, because after being reflected onto itself or turning 180 degrees, you would be transforming onto itself. I hope this helps!
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3 years ago
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Perform the following operations and write the answers in radical form. Part A:√7+√3+√98−√18 Part B:3√5−3√11+2√121−3√90
Sveta_85 [38]

Answer:

  1. \sqrt{7}+\sqrt{3}+4\sqrt{2}
  2. 3\sqrt{5}-3\sqrt{11}+22-9\sqrt{10}

Step-by-step explanation:

Part A ;

\sqrt{7} +\sqrt{3} +\sqrt{98} -\sqrt{18} \\\\\sqrt{98}=7\sqrt{2}\\\sqrt{18}=3\sqrt{2}\\\\=\sqrt{7}+\sqrt{3}+7\sqrt{2}-3\sqrt{2}\\\\\mathrm{Add\:similar\:elements:}\:7\sqrt{2}-3\sqrt{2}=4\sqrt{2}\\\\=\sqrt{7}+\sqrt{3}+4\sqrt{2}

Part B ;

3\sqrt{5}  - 3\sqrt{11} + 2\sqrt{121} -3\sqrt{90} \\\\2\sqrt{121}=22\\3\sqrt{90}=9\sqrt{10}\\\\=3\sqrt{5}-3\sqrt{11}+22-9\sqrt{10}

8 0
4 years ago
What is the sum? StartFraction 3 Over x squared minus 9 EndFraction StartFraction 5 Over x 3 EndFraction.
V125BC [204]

The sum of the two fractional number, which consist in the variable <em>x</em> is in the polynomial function,

f(x)=\dfrac{5x-12}{(x+3)(x-3)}

<h3>What is the sum of fraction number?</h3>

Fraction number is the number which is a part of a whole number. It is written with a numerator and denominator.

Fraction number are written as,

\dfrac{a}{b}

Here (a) is the numerator and (b) is the denominator.

To find the sum of two fraction numbers, cross multiply both the numbers or find the least common factor as denominator.

The first fraction number given in the problem is,

\dfrac{3}{x^2+9}

The second fraction number given in the problem is,

\dfrac{5}{x+3}

Let the sum of these number is f(x). Thus,

f(x)=\dfrac{3}{x^2-9}+\dfrac{5}{x+3}\\f(x)=\dfrac{3}{(x+3)(x-3)}+\dfrac{5}{x+3}\\

Solve it further as,

f(x)=\dfrac{3+5(x-3)}{(x+3)(x-3)}\\f(x)=\dfrac{3+5x-15}{(x+3)(x-3)}\\f(x)=\dfrac{5x-12}{(x+3)(x-3)}

Thus, the sum of the two fractional number is,

f(x)=\dfrac{5x-12}{(x+3)(x-3)}

Learn more about the fraction number here:

brainly.com/question/78672

6 0
2 years ago
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Answer:

102°

Step-by-step explanation:

This is an isosceles triangle

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Divide -3 to both sides:

\sf y=\boxed{\sf 8}
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