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2 years ago

Python Coding:

Computers and Technology

1 answer:

leva [86]2 years ago

5 0

Answer:

# Here we are asking the user for a number two times

userInput1 = input("Enter any #: ")

userInput2 = input("Enter any # again: ")

# We compare if userInput1 is greater than userInput2

if(userInput1 > userInput2):

# Print userInput1 if userInput1 is greather than userInput2

print("First Number: " + userInput1)

# Otherwise, print userInput2

else:

print("Second Number: " + userInput2)

# Initiate a while-loop

while(True):

# The lines below are from above

userInput1 = input("\nEnter any #: ")

userInput2 = input("Enter any # again: ")

if(userInput1 > userInput2):

print("First Number: " + userInput1)

else:

print("Second Number: " + userInput2)

# We ask the user whether they would like to stop

stop = input("\nWould you like to stop? (Yes or No)")

# Compare the String stop with "Yes"

if(stop == "Yes"):

# If true then break

break

Explanation:

The use of \n is unnecesary, but it skips a line and provides more readability.

You might be interested in

Write a method that takes three numerical String values and sums their values.

Sphinxa [80]

Answer:

<u>Algorithm</u>:

Take a int variable c=0.
Run the loop from 0 to String length.
Get the each index value using charAt() method which will return the char value.
Convert that char into int by typecasting or any other way.
Now check that ASCII fall into the range of 48-57 for 0-9 int number.
If it matches then first convert that number into integer using Integer.parseInt().
Then add with the c and store to the same variable i.e c.
Repeat from 3-7 till the end of the loop.
At the end of loop , Print c outside the loop.

Explanation:

// Java program to calculate sum of all numbers present

// in a string containing alphanumeric characters

class GFG

{

// Function to calculate sum of all numbers present

// in a string containing alphanumeric characters

static int findSum(String str)

{

// A temporary string

String temp = "";

// holds sum of all numbers present in the string

int sum = 0;

// read each character in input string

for(int i = 0; i < str.length(); i++)

{

char ch = str.charAt(i);

// if current character is a digit

if (Character.isDigit(ch))

temp += ch;

// if current character is an alphabet

else

{

// increment sum by number found earlier

// (if any)

sum += Integer.parseInt(temp);

// reset temporary string to empty

temp = "0";

}

// atoi(temp.c_str()) takes care of trailing

// numbers

return sum + Integer.parseInt(temp);

}

// Driver code

public static void main (String[] args)

{

// input alphanumeric string

String str = "1abc5yz7";

System.out.println(findSum(str));

}

4 0

3 years ago

Read 2 more answers

True or false? The largest component of a database is a field.

Sergio [31]

Maybe true,or maybe false,you never know.

7 0

4 years ago

Read 2 more answers

Just five types of pointing device,list

posledela

Answer:

five types of pointing devices

Explanation:

Ponting devices

Pointing means point something and the pointing devices are the input /peripheral devices those are used to point the pointer on the screen. We do move cursor on the screen to open the files or any icon.

There are many types of pointing devices but these are quite common which are given below

Computer mouse
Finger on touch screen.
Joystick.
Leap Motion.
Light pen (pen)

1.Mouse

Mouse is most common type of input device that is used for pointing the data on the screen. We press it with our hands and keep pointing the things.

There are three types of mouse

optical mouse
wireless mouse
trackball mouse.

2. Finger on touch screen

In this type of movement the fingers are input devices those we use to see the movement of pointer on the screen and this is most common in this century.

3.Joystick.

Joystick is another input device to point the cursor but it is mostly used in games. Children can use it smartly so it is inculcated in games usually.

4. Leap Motion

The Leap Motion (LM) controller is a latest 3D sensing device for hand posture interaction with a computer. It is having the capability sense the location of the fingers of the hands, as well as the palm position.

5.Light Pen

this is another pointing device which is mostly used to highlight and select the data on the screen.

Note: All of these above pointing devices are most common used now a days. These devices are having new conventions day by day for the ease of user. This era is basically the era of IT ,so the use of computer must be so easy and conventional for the user so, the innovations and improvement in such devices is made side by side.

3 0

3 years ago

Write a program that sorts an array of 10 integers using bubble sort. In the bubble sort algorithm, smaller values gradually “bu

blsea [12.9K]

Answer:

#include<iostream>

using namespace std;

int main(){

//initialization

int arr1[10] = {2,4,6,1,7,9,0,3,5,8};

int temp;

int size_arr;

//nested for loop

for(int i=0;i<size_arr-1;i++){

for(int j=0;j<size_arr-i-1;j++){

if(arr1[j]>arr1[j+1]){ //compare

//swapping

temp = arr1[j];

arr1[j]=arr1[j+1];

arr1[j+1]=temp;

}

//display the each element

for(int i=0;i<10;i++){

cout<<arr1[i]<<" ";

}

return 0;

}

Explanation:

Create the main function and declare the variable and defining the array with 10 values.

take the nested for loop, nested loop means loop inside another loop.

the outer loop traverse in the array from 0 to size-1.

and inside loop traverse from 0 to size -i-1, because for every cycle of the outer loop the one element is sorted at the end. so, we do not consider the element from the last for every cycle of the outer loop. That's why (size-i-1)

In the bubble sort, the first element compares with the second element and if the first id greater than the second then swap the value. so, for the above algorithm, we take the if statement and it checks the condition if the condition becomes true then the swap algorithm executes.

we take a third variable for swapping. after that, if the outer loop condition false it means all elements will traverse and then the loop will terminate.

and finally, take another for loop and display the output.

8 0

4 years ago

Write a MIPS program to continuously generate the following series of integers: 1, 2, 3, 6, 9, 18, 27, 54, 81, and so on. Use st

Pachacha [2.7K]

Answer:

Explanation:

Here is a working solution in MIPS

.data

space: .asciiz ", "

.text

li $t1, 1 #Start at 1

li $t2, 1 #Store last value

li $t4, 1000 #terminate at 1000

li $t7, 2 #For division (divide by 2)

loop:

li $v0, 1

add $a0, $t1, $zero #print $t1

syscall

div $t1, $t7 #divide $t1 by 2

mfhi $t5 #get the remainder

move $t6, $t1 #hang on to what $t1 was originally

beqz $t5, even #if the remainder is 0, it's even

add $t1,$t1,$t1 #it's odd, so add to itself

move $t2, $t6 #store what $t1 was originally to last value

bgt $t1, $t4, done #if the number is over 1000, we're done

li $v0, 4 #Print a comma and space

la $a0, space

syscall

j loop

even:

add $t1,$t1,$t2 #set $t1 = $t1 + Last value ($t2)

move $t2, $t6 #store what $t1 was originally to last value

bgt $t1, $t4, done #if the number is over 1000, we're done

li $v0, 4 #Print a comma and space

la $a0, space

syscall

j loop

done:

3 0

4 years ago