Answer:
Option C. Security+ is the correct answer.
Explanation:
The loop terminates when "xxxxx" is read in. If the word is land, the string followed by "land" get outputted. The same with air, and water.
Explanation:
int land = 0;
int air = 0;
int water = 0;
String word = "";
while(!(word.equals("xxxxx"))) {
word = stdin.next();
if(word.equals("land")) {
land++;
}else if(word.equals("air")) {
air++;
}else if(word.equals("water")) {
water++;
}
}
System.out.println("land:" + land);
System.out.println("air:" + air);
System.out.println("water:" + water);
You would need to show a pic
Answer:
void swapints(int *j,int *k)//Function definition.
{
*j=*j+*k-(*k=*j); //value swapping.
}
swapints(&j,&k);//call the function.
Explanation:
- The above function definition takes the address of j and k variables which is stored on the pointer variable j and k.
- Then the pointer variable uses the j and k value for the above expression, and the user does not need to return the value of j and k.
- But when the user prints the value of the j and k variable, then he gets the swapping value of the j and k variable.
- The user needs to know that the "int j" is a normal variable, but "int *j" is a pointer variable that is used to take the address of j variable.
