Answer:
- Transform binary or unary M:N relationship or associative entity with its own key.
Explanation:
Transform binary relation is described as the method through which a decimal can easily be converted into binary while the unary relationship is described as a relationship in which both the two participants occurs from the same entity.
In the given case, 'transform binary or unary M:N relationship' can be created using 'the primary key linked with the relationship plus any non-key aspects of the relationship and the primary keys of the related entities' as it displays the existence of a relationship between the occurrences of a similar set of the entity i.e. associative entity here.
Answer:
The correct answer to the following question will be option C.
172.16.80.1-172.16.87.254
Explanation:
IP Address: IP Address stands for Internet Protocol Address, a unique numerical label allotted to every computer network that are connected to the network of the computer and communicate through the internet protocol.
- An IP address can be separated by periods and having four numbers that are called Octet. Range of IP address can be from 0 to 255.
- We have to keep the first 21 bits and start setting all from the 22nd bit on to 0 (zero).
- To get the suitable and the correct range of the address, we add and subtract 1 from the given broadcast address i.e.,172.16.85.0/21.
So, option C is the right answer and no other option is usable according to the given explanation and the address given by the administrator.
Answer:
Explanation:
#include <iostream>
using namespace std;
int costdays(int);
int costhrs(int,int);
int main()
{
int dd,hh,mm,tmph,tmpd,tmpm=0;
int pcost,mcost=0;
cout<<"Enter Parking time" << endl;
cout<<"Hours: ";
cin>>hh;
cout<<"Minutes: ";
cin>>mm;
if (mm>60)
{
tmph=mm/60;
hh+=tmph;
mm-=(tmph*60);
}
if (hh>24)
{
tmpd=hh/24;
dd+=tmpd;
hh-=(tmpd*24);
}
if ((hh>4)&&(mm>0))
{
pcost+=costdays(1);
}
else
{
mcost=costhrs(hh,mm);
}
cout<<"Total time: ";
if (dd>0)
{
cout<<dd<<"days ";
pcost+=costdays(dd);
}
pcost+=mcost;
cout<<hh<<"h "<<mm<<"mins"<<endl;
cout<<"Total Cost :"<<pcost<<"Won";
return 0;
}
int costdays(int dd)
{
return(dd*25000);
}
int costhrs(int hh,int mm)
{
int tmpm, tmp=0;
tmp=(hh*6)*1000;
tmp+=(mm/10)*1000;
tmpm=mm-((mm/10)*10);
if (tmpm>0)
{
tmp+=1000;
}
return(tmp);
}
