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jeyben [28]
2 years ago
10

-0.7=-7/9z help me pleasseeee!​

Mathematics
1 answer:
9966 [12]2 years ago
7 0
The answer is 0.9 if z is in the numerator and if it is in the denominator it is 1/9
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Help please thank you!
monitta

Answer:

• multiplied by 4p: (x -h)² +4pk = 0

• zeros for k > 0: none

• zeros for k = 0: one

• zeros for k < 0: two

Step-by-step explanation:

a) Multiplying by 4p removes the 1/(4p) factor from the squared term, but adds a factor of 4p to the k term. (It has no effect on the subsequent questions or answers, so we wonder why we're doing this.) The result is ...

(x -h)² +4pk = 0

__

b) The value of k is the vertical location of the vertex of the parabola with respect to the x-axis. The parabola opens upward, so for k > 0, the parabola does not cross the x-axis, and the number of real zeros is zero. (There are two complex zeros.)

__

c) As in part b, the value of k defines the vertex location. When it is zero, the vertex of the parabola is on the x-axis, so there is one real zero (It is considered to have multiplicity 2.)

__

d) As in part b, the value of k defines the vertex location. When it is negative, the vertex of the parabola is below the x-axis. Since the parabola opens upward, both branches will cross the x-axis, resulting in two real zeros.

_____

The attached graph shows a parabola with p=1/4 and h=2. The values shown for k are +1, 0, and -1. The coordinates of the real zeros are shown.

8 0
3 years ago
What is the equation of a circle with center (-3, -1) that contains the point (1, 2)?
Leno4ka [110]
So, we know the center is at -3,-1, ok

hmmm what's the radius anyway?   well, we know that there's a point at 1,2 that is on the circle's path...hmmmm what's the distance from the center to that point?  well, is the radius, let's check then.

\bf \textit{distance between 2 points}\\ \quad \\&#10;\begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%  (a,b)&#10;&({{ -3}}\quad ,&{{ -1}})\quad &#10;%  (c,d)&#10;&({{ 1}}\quad ,&{{ 2}})&#10;\end{array}\qquad &#10;%  distance value&#10;d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}&#10;\\\\\\&#10;r=\sqrt{[1-(-3)]^2+[2-(-1)]^2}\implies r=\sqrt{(1+3)^2+(2+1)^2}&#10;\\\\\\&#10;r=\sqrt{16+9}\implies r=\sqrt{25}\implies r=5

so, what's the equation of a circle with center at -3, -1 and a radius of 5?

\bf \textit{equation of a circle}\\\\ &#10;(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2&#10;\qquad &#10;\begin{array}{lllll}&#10;center\ (&{{ h}},&{{\quad  k}})\qquad &#10;radius=&{{ r}}\\&#10;&-3&-1&5&#10;\end{array} &#10;\\\\\\\&#10;[x-(-3)]^2+[y-(-1)]^2=5^2\implies (x+3)^2+(y+1)^2=25
7 0
2 years ago
Average winter temperatures in 45 states were recorded and divided by geographic region. Choose True or False for each statement
mash [69]
This will be false because that’s not the average winter temperatures in 45 states
7 0
3 years ago
Read 2 more answers
1. Write the interval shown on the number line
shusha [124]

Answer:

x\geq 5

\{x\  |\  x \geq 5\}   OR {5, 6, 7, 8, .....}

Step-by-step explanation:

First of all, let us have a look at the interval shown on the number line and try to understand it properly.

The number line shows positive numbers starting from 3 that means numbers indicated will be positive numbers.

The number highlighted starts from 5 and there is filled circle at 5.

So, 5 is included in the interval.

The arrow is from 5 towards 8 and so on..

That means Numbers greater than or equal to 5 are represented by the interval.

So, writing as an inequality

Let x represents one of the numbers.

Hence, inequality can be written as:

x\geq 5

Using the set notation:

\{x\  |\  x \geq 5\}

OR

{5, 6, 7, 8, .....}

3 0
3 years ago
Simplify. (-2)^-3 <br> ?????
Licemer1 [7]
Remember
(ab)^c=(a^c)(b^c) and
x^{-m}= \frac{1}{x^m}
so
(-2)^{-3}= \frac{1}{(-2)^3}= \frac{1}{(-1)^3(2)^3}=\frac{1}{(-1)(8)}=\frac{1}{-8}=\frac{-1}{8}
3 0
3 years ago
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