Answer:
0.571428571429 grams per cm³
Step-by-step explanation:
density = mass/volume
Let’s calculate the volume V of the pyramid :
V = (1/3)×base×height
= (1÷3)×(5×7)×9
= 105 cm³
Then
The density = mass/volume
= 60÷105
= 0.571428571429
Answer:
4/5
Step-by-step explanation:
Use the formulae
y2-y1 divided by x2- x1 then you will get your slope
Answer:
slope is -5
Step-by-step explanation:
This equation is in slope-intercept form:
where m is the slope and b is the y-intercept.
In the given equation, the slope is -5 and the y-intercept is 1.
Length of the walkway that needs to be tiled = 60 feet
Width of the walkway that needs to be tiled = 2 feet.
Then
Area of the walkway that needs to be tiled = Length * Breadth
= 60 * 2 square feet
= 120 square feet
Now
Length of the tiles sold by the local store = 2 feet
Width of the tiles sold by the local store = 2 feet
Area covered by the tiles sold by the local store = 2 * 2 feet
= 4 square feet
Number of tiles in a box = 6
Then
Total area covered by a box of tile = (6 * 2) square feet
= 12 square feet
Then
The number of boxes required by Sean = (120/12)
= 10
So 10 boxes of tiles are needed by Sean and his father.
Answer:
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
<u>Calculus</u>
Implicit Differentiation
The derivative of a constant is equal to 0
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Product Rule:
Chain Rule:
Quotient Rule:
Step-by-step explanation:
<u>Step 1: Define</u>
-xy - 2y = -4
Rate of change of the tangent line at point (-1, 4)
<u>Step 2: Differentiate Pt. 1</u>
<em>Find 1st Derivative</em>
- Implicit Differentiation [Product Rule/Basic Power Rule]:
- [Algebra] Isolate <em>y'</em> terms:
- [Algebra] Factor <em>y'</em>:
- [Algebra] Isolate <em>y'</em>:
- [Algebra] Rewrite:
<u>Step 3: Find </u><em><u>y</u></em>
- Define equation:
- Factor <em>y</em>:
- Isolate <em>y</em>:
- Simplify:
<u>Step 4: Rewrite 1st Derivative</u>
- [Algebra] Substitute in <em>y</em>:
- [Algebra] Simplify:
<u>Step 5: Differentiate Pt. 2</u>
<em>Find 2nd Derivative</em>
- Differentiate [Quotient Rule/Basic Power Rule]:
- [Derivative] Simplify:
<u>Step 6: Find Slope at Given Point</u>
- [Algebra] Substitute in <em>x</em>:
- [Algebra] Evaluate: