Answer:
- area: 133.5 m²
- perimeter: 52.02 m
Step-by-step explanation:
<h3>Area</h3>
The area of each trapezoid can be found using the relevant formula:
A = 1/2(b1 +b2)h . . . . b1, b2 are the base lengths; h is the height
For the top trapezoid, the height is 13 m-7 m = 6 m, so the area is ...
A = 1/2(8 m +5 m)(6 m) = 39 m²
The area of the bottom trapezoid is ...
A = 1/2(10 m +17 m)(7 m) = 94.5 m²
The area of the shape is the sum of the areas of the two trapezoids.
area = 39 m² +94.5 m² = 133.5 m² . . . . area of the figure
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<h3>Perimeter</h3>
The horizontal lengths are all marked, but the slant lengths are not. There are no angles or other information given that can help determine the slant lengths. In order to answer the question, we can assume that the trapezoids are isosceles. Then the base of the right triangle shown in the top trapezoid is (8 -5)/2 = 1.5 m. The height is 6 m. The Pythagorean theorem tells us the slant length is ...
s1 = √(1.5² +6²) ≈ 6.1847 . . . . meters
Similarly, the base length of the right triangle shown next to the bottom trapezoid is (17 -10)/2 = 3.5 m. The height is 7 m. The slant length of that one is ...
s2 = √(3.5² +7²) ≈ 7.8262 . . . . meters
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The perimeter is the sum of the lengths of the sides. Note that the 17 m dimension includes 8 m that are not part of the boundary of the figure. The sum of lengths of the horizontal edges is ...
10 m +(17 -8 m) +5 m = 24 m
The sum of the lengths of the slant edges is ...
2·s1 +2·s2 = 2(6.1847 +7.8262) ≈ 28.02 . . . . meters
The perimeter of the figure is the sum of horizontal lengths and slant lengths:
24 m + 28.02 m = 52.02 m . . . . perimeter of the figure
