Let Q1 and Q2 be the quotients from dividing 32 and 58 respectively.Then 32 Q1 + 30 = 58 Q2 + 4432 Q1 = 58 Q2 + 1416 Q1 = 29 Q2 + 716 Q1 = (16 + 13)Q2 + 716 Q1 = 16 Q2 + 13 Q2 + 716(Q1 - Q2) = 13 Q2 + 7Because Q1 and Q2 are integers, we have to find Q2 whereby 13Q2 + 7 is divisible by 16.After some try-and-error, we get Q2 = 13. That is 13*13 + 7 = 176Therefore, Q1 - Q2 = 11 --> Q1 - 13 = 11 --> Q1 = 2432*24 + 30 = 58*13 + 44 = 798.I am 798
To solve the exponential growth application question we proceed as follows;
suppose the time, t between 1993 to 2000 is such that in 1993, t=0 and in 2000, t=7.
Note theta the population is in millions;
The exponential formula is given by:
f(t)=ae^(kt)
where;
f(t) =current value
a=initial value
k=constant of proportionality
t=time
substituting the values we have in our formula we get:
132=127e^(7k)
132/127=e^(7k)
introducing the natural logs we get:
ln (132/127)=7k
k=[ln(132/127)]/7
k=0.0055
Thus our formula will be:
f(t)=127e^(0.0055t)
The population in 2008 will be:
f(t)=127e^(15*0.0055)=127e^(0.0825)=137.922
Thus the population in 2008 is appropriately 138 million.
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Answer: 1 and 7
Step-by-step explanation:
Since 7 is prime, you only have 1 and 7 multiplied to get 7 and when added together, form 8.
Answer:
N = 6
Step-by-step explanation:
-15 + 6 or -15 - (-6) = -9
