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astra-53 [7]
2 years ago
8

What's a real number?

Mathematics
2 answers:
Afina-wow [57]2 years ago
8 0

Answer:

Real Numbers are numerical values that can represent distance on a line. An example of it being one is 15 and an example of it NOT being one is ∞.

aksik [14]2 years ago
4 0

Answer:

number 1 is a real number and 2 and 3 and 4 and 5 and 6 and 7 and 8 and 9

Step-by-step explanation:

a real number is a value of a continuous quantity that can represent a distance along a line.

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I need help w/ this!! thank you
Fittoniya [83]
<h3><u>Answer:</u></h3>

\boxed{\pink{\sf \leadsto Yes \ there \ is \ a \ solution \ of \ the \ given \ inequality .}}

<h3><u>Step-by-step explanation:</u></h3>

A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.

The inequality given to us is :-

\bf\implies |2y + 3 | - 1 \leq 0 \\\\\bf\implies |2y+3|\leq 1 \\\\\bf\implies (|2y+3|)^2 \leq 1^2  \\\\\bf\implies (2y+3)^2 \leq 1  \\\\\bf\implies (2y)^2+3^2+2(2y)(3) \leq 1  \\\\\bf\implies 4y^2+9+12y - 1 \leq 0  \\\\\bf\implies 4y^2+12y+8 \leq 0 \\\\\bf\implies 4( y^2 + 3y + 2 ) \leq 0  \\\\\bf\implies y^2+3y +2 \leq 0 \:\:\bigg\lgroup \purple{\bf Standard \ form \ of \ inequality }\bigg\rgroup   \\\\\bf\implies y^2y+2y+y+2 \leq 0  \\\\\bf\implies y(y+2)+1(y+2)\leq 0  \\\\\bf\implies ( y+2)(y+1)\leq 0  \\\\\bf\implies \boxed{\red{\bf y \leq (-2) , (-1) }}

Let's plot a graph to see its interval . Graph attached in attachment .

Now we can see that the Interval notation of would be ,

\boxed{\boxed{\orange \tt \purple{\leadsto}y \in [-2,-1] }}

<h3><u>Hence</u><u> the</u><u> </u><u>standa</u><u>rd</u><u> </u><u>form</u><u> </u><u>of</u><u> </u><u>inequa</u><u>lity</u><u> </u><u>is</u><u> </u><u>y²</u><u>+</u><u>3y</u><u> </u><u>+</u><u>2</u><u> </u><u>≤</u><u> </u><u>0</u><u> </u><u>and</u><u> </u><u>the </u><u>Solution</u><u> </u><u>set</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>ineq</u><u>uality</u><u> </u><u>is</u><u> </u><u>[</u><u> </u><u>-</u><u>2</u><u> </u><u>,</u><u> </u><u>-</u><u>1</u><u> </u><u>]</u><u> </u><u>.</u></h3>
4 0
2 years ago
ving as a relation, state the domain and range, then determine if it is a6.2X-2 0.-2Relation:DomainRangeFunction3 i
Travka [436]

The relation is the set of ordered pairs of point drawn in the graph

The points are:

(-2, 3), (0, 1), (2, -1), (3, -2)

So the relation is:

R = {(-2, 3), (0, 1), (2, -1), (3, -2)}

The domain is the values of x in the ordered pairs

x = -2, 0, 2, 3

The domain = {-2, 0, 2, 3}

The range is the values of y in the ordered pairs

y = 3, 1, -1, -2

Arrange them in the set

The range = {-2, -1, 1, 3}

7 0
1 year ago
Question 6 of 25
sladkih [1.3K]

Answer:

C

Step-by-step explanation:

When you put a down payment on something that means you are buying/reserving for yourself. So when he's paying per month he will keep the ring until he misses a payment or keeps it until he pays it off

A P E X

Please Give brainliest

7 0
3 years ago
Read 2 more answers
The Brown family bought 9 bags of cookies. Each bag had 16 cookies. They have since eaten 26 of the cookies. How many cookies do
grigory [225]

Answer:

118 cookies

Step-by-step explanation:

1. 9x 16  

2.144-26

And then get 118! Have a nice day YW!!!!!???

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2 years ago
F(x) = 2/x, g(x) = |x| -1 <br><br> what is the domain of (fog) (x)?<br><br> WILL MARK BRAINLIEST
DIA [1.3K]

Answer:

x≠-1,1

Step-by-step explanation:

f(g(x)) is a composition where g(x) is is substituted for x in f(x).

Recall, f(x) is 2/x. So we write 2/|x|-1. This places x in the denominator and 0 cannot be in the denominator x. Any value of x that makes the denominator 0 will not be in the domain.

|x|-1=0

|x|=1

x=1,-1

5 0
3 years ago
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