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fenix001 [56]
3 years ago
13

Which of the following statements is true about any sphere ? It has only two dimensions . Its cross section is in the shape of a

circle . Its surface area is measured in cubic units . D. It has a radius that is always a perfect square .
Mathematics
1 answer:
ser-zykov [4K]3 years ago
8 0

Answer:

1) It has only two dimensions .   FALSE

2). Its cross section is in the shape of a circle .   TRUE

3) Its surface area is measured in cubic units.      FALSE

4) It has a radius that is always a perfect square.     FALSE.

Step-by-step explanation:

Sphere: Sphere is a 3 dimensional perfectly round object.

Here, all point lying at the circumference are at equal distance from the center.

The given statements are:

1) It has only two dimensions .

FALSE, a 2 D figure is a circle not a sphere. Sphere is 3 D.

2). Its cross section is in the shape of a circle .

TRUE, any cross section of a sphere is always a circle.

3) Its surface area is measured in cubic units.

FALSE, Surface area of a sphere = 4 \pi r^2 sq. units

4) It has a radius that is always a perfect square.

FALSE. A sphere can be of any possible radius.

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I WILL GIVE BRAINLIEST PLEASE HELP
Greeley [361]

Answer:

The slope of AB and BC are the same.

The initial value is 60 m and the slope is 40 m/min.

Step-by-step explanation:

The graph shows the depth, y, in meters, of a shark from the surface of an ocean for a certain amount of time, x, in minutes.

See the graph attached.

Part A : If we consider two right triangles one Δ ABD and Δ BCE, where D(2,100) and E(1,60) points.

Now, those two triangles are similar and hence the slope of line segment AB will be \tan \theta  = \frac{AD}{BD} = \frac{140 - 100}{2 - 1} = 40.

Again, the slope of the line segment BC will be

\tan \alpha = \frac{BE}{CE} = \frac{100 - 60}{1 - 0} = 40

Hence, \theta = \alpha and the slope of AB and BC are the same. (Answer)

Part B : From the graph, it is clear that the initial value of the graph is 60 m and it represents that initial position of the shark i.e. at t = 0 min, the shark was at a depth of 60 m from the water surface.

The slope of the graph is 40 means the rate of change of distance from the Ocean surface of the shark with respect to time in minutes will be 40 m per min. (Answer)

7 0
3 years ago
825 students 55 teachers what is ratio
kumpel [21]
15 students per teacher because 825/55=15
7 0
3 years ago
Pls anwer this qestion it is worth 30 points
Sveta_85 [38]

Answer:

49

Step-by-step explanation:

25b² + 70b + ....

( 5b + 7)² = 5×5b² + 2×5×7b + 7×7 = 25b² + 70b + 49

6 0
3 years ago
Some one factor 3x^2+7x-20
mylen [45]
Split it up
3x^2+12x-5x-20
group
(3x^2+12x)+(-5x-20)
factor
(3x)(x+4)+(-5)(x+4)
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6 0
3 years ago
The estimate of the population proportion should be within plus or minus 0.02, with a 90% level of confidence. The best estimate
Rudiy27

Answer:

The sample size required is 910.

Step-by-step explanation:

The confidence interval for population proportion is:

CI=\hat p\pm z_{ \alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n} }

The margin of error is:

MOE=z_{ \alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n} }

Given:

\hat p = 0.16\\MOE= 0.02\\Confidence\ level =0.90

The critical value of <em>z</em> for 90% confidence level is:

z_{\alpha /2}=z_{0.10/2}=z_{0.05}=1.645 *Use a standard normal table.

Compute the sample size required as follows:

MOE=z_{ \alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n} }\\0.02=1.645\times \sqrt{\frac{0.16(1-0.16)}{n} }\\n=\frac{(1.645)^{2}\times 0.16\times (1-0.16)}{(0.02)^{2}} \\=909.2244\\\approx910

Thus, the sample size required is 910.

5 0
4 years ago
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