Which of the following statements is true about any sphere ? It has only two dimensions . Its cross section is in the shape of a
1 answer:
Answer:
1) It has only two dimensions . FALSE
2). Its cross section is in the shape of a circle . TRUE
3) Its surface area is measured in cubic units. FALSE
4) It has a radius that is always a perfect square. FALSE.
Step-by-step explanation:
Sphere: Sphere is a 3 dimensional perfectly round object.
Here, all point lying at the circumference are at equal distance from the center.
The given statements are:
1) It has only two dimensions .
FALSE, a 2 D figure is a circle not a sphere. Sphere is 3 D.
2). Its cross section is in the shape of a circle .
TRUE, any cross section of a sphere is always a circle.
3) Its surface area is measured in cubic units.
FALSE, Surface area of a sphere = sq. units
4) It has a radius that is always a perfect square.
FALSE. A sphere can be of any possible radius.
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Based on the table attached, the class boundaries are as follows: 43.5, 49.5, 53.5, 59.5, 63.5, 69.5, 73.5, 79.5.
<h3 /><h3>What is the frequency distribution about?</h3>Temperature (°F) Frequency
40-44 1
45-49 3
50-54 5
55-59 11
60-64 7
65-69 7
70-74 1
A. Viewing at the frequency table, we find that the lower class limits of two consecutive classes are 40 and 44, respectively. Thus the class width is:
Class width = 44 − 40= 4
B: One can find the class midpoints by putting the average of the lower and upper class limits. So the midpoint of the first class is seen below:
= 40 - 44 = = 42. In a similar way, we find the rest.
C. The Class boundaries is known to be that which separate the classes removing the class limits. The class boundaries are as follows:
43.5, 49.5, 53.5, 59.5, 63.5, 69.5, 73.5, 79.5
Therefore, Based on the table attached, the class boundaries are as follows: 43.5, 49.5, 53.5, 59.5, 63.5, 69.5, 73.5, 79.5.
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