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2 years ago

Please help it’s urgent this assignment is almost due!!!?

Mathematics

2 answers:

Advocard [28]2 years ago

6 0

The bottom answer. Bc I am learning this is class.

topjm [15]2 years ago

3 0

Answer: 2 the function a is less than the slope of function b

Step-by-step explanation: put the points on the grid and compare the lines. Whichever one is the steeper line has the greater slope.

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OK can someone help me on this one...?

aksik [14]

2. multiplication property of equality

3. subtraction property of equality

4. addition property of equality

5. division property of equality

8 0

3 years ago

Find the length of the third side. If necessary, write in simplest radical form.<br> 10<br> 7

oksian1 [2.3K]

Answer:

$\sqrt{51}$

Step-by-step explanation:

10²-7² (C squared minus B squared equals A squared) (basically Pythagorean theorem but reversed)

100-49= 51 (square the numbers and subtract)

$\sqrt{51}$

6 0

2 years ago

S = 1 / g t ² π, solve for t

Finger [1]

$s = \frac{1}{g {t}^{2}\pi }$

multiply through by

$g {t}^{2} \pi$

$s \times g {t}^{2} \pi = \frac{1}{g {t}^{2} \pi} \times g {t}^{2} \pi$

$sg {t}^{2} \pi = 1$

dividing through by

sgπ

${t}^{2} = \frac{1}{sg\pi}$

$t = \sqrt{ \frac{1}{sg\pi} }$

4 0

3 years ago

Read 2 more answers

Solve your equations below and right the algebraic steps, n/12 = 10

sdas [7]

$\frac{n}{12}=10$

Multiply both sides of the equation by 12

$\frac{n}{12}\times12=10\times12$ $n=\text{ 120}$

7 0

1 year ago

Based on past experience, a telemarketing firm has found that calls to prospective customers take an average of 2.0 minutes, wit

xenn [34]

Answer: Our required probability would be 0.9641.

Step-by-step explanation:

Since we have given that

Number of hours he works a day = 8

So, Number of minutes he worked in a day = $8\times 60=480\ minutes$

Number of calls = 220

So, Average $=\bar{x}=\dfrac{480}{220}=2.18\ minutes$

Standard deviation $=s=\dfrac{\sigma}{\sqrt{n}}=\dfrac{1.5}{\sqrt{220}}=0.10$

Mean = μ = 2.0 minutes

Standard deviation = σ = 1.5 minutes

Using the normal distribution, we get that

$z=\dfrac{\bar{x}-\mu}{s}\\\\z=\dfrac{2.18-2.0}{0.10}\\\\z=1.8$

So, the probability that Albert will meet or exceed his quota would be

$P(X\leq 2.18)=P(z\leq 1.8)=0.9641$

Hence, our required probability would be 0.9641.

6 0

3 years ago