Which equation represents the hyperbola that has its Foci farthest from its Center

Mathematics

2 answers:

kogti [31]4 years ago

6 0

Equation of hyperbola is given by
$\frac{(x-h)^2}{a^2}- \frac{(y-k)^2}{b^2}=1$

Where the centre is (h, k) and the foci is (h-c, k) and (h+c, k)

c is obtained from $c^2=a^2+b^2$

We'll calculate the distance for each option in turn

Option A

$\frac{(x-2)^2}{8^2}- \frac{(y-1)^2}{7^2}=1$

The centre is (2, 1)

Work out the value of 'c' to find the coordinates of two focus
We have $a^2=8^2$ and $b^2=7^2$
$c^2=a^2+b^2=8^2+7^2=64+49=113$
$c= \sqrt{113}$

The coordinate of foci is $(2- \sqrt{113}, 1)$ and $(2+ \sqrt{113}, 1)$

Notice that the y-coordinate of the focus is the same with the y-coordinate of the centre, so we'll only need to work out the horizontal distance between one foci to the centre (the centre of a hyperbola is the same distance to both focus)

Distance from foci to centre = $(2+ \sqrt{113})-2=12.6-2=10.6$
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Option B

Centre (-2, 3)
c² = a² + b² = 19² + 11² = 482
c = √482
c = 21.95

The coordinates of focus = (-2+21.95, 3) and (-2-21.95, 3)
= (19.95, 3) and (-23.95, 3)

Distance from one foci to the centre is = 19.95 - (-2) = 21.95 units
If the other foci is used for the calculation, the answer will be the same
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Option C

Centre (1, 2)
c² = 6² + 9² = 36 + 81 = 117
c = √117
c = 10.8

Coordinates of focus = ((1-10.8), 2) and ((1+10.8), 2)
= (-9.8, 2) and (11.8, 2)

Distance between foci and centre = 11.8 - 1 = 10.8 units
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Option D

Centre (5, -3)

c² = 5² + 19² = 386
c = √386
c = 19.6

Coordinates of focus are ((5-19.6), -3) and ((5+19.6), -3) = (-14.6, -3) and (24.6, -3)

Distance foci - centre = 24.6 - 5 = 19.6
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The equation that gives the furthest distance from centre to foci is given by option B