Answer: I think there is a mistake for the first one because I did the math and I got 200 added but then there are more answers to this one, I added all the others by 200 and got the next number but then when I got to 6,300 I can't get the 6,700. I get something else, I add 6,000 with 200, and then I get 6,200 instead of getting 6,300. Then I added that 6,200 and 200 and got 6,400. I am confused with the second one, can you please help me understand that one. The third one is also confusing, The one is 12 nuggets eaten per minute. The fifth I am not sure if that is a solvable question, The sixth one I am not sure but I think that it is 0.066667. The seventh one doesn't even make any sense to me.
Explanation: I am sorry this was so long, I was trying to make sense of these questions. Also if this is ALL wrong sorry for even trying.
The Correct choices are :
- the dependent variable is y
- the rate of change is not constant
- independent variable is x
- This is a negative relationship
- The relationship is nonlinear
Answer:
b
Step-by-step explanation:
sorry if i am wrong
Hmm, the 2nd derivitve is good for finding concavity
let's find the max and min points
that is where the first derivitive is equal to 0
remember the difference quotient
so
f'(x)=(x^2-2x)/(x^2-2x+1)
find where it equals 0
set numerator equal to 0
0=x^2-2x
0=x(x-2)
0=x
0=x-2
2=x
so at 0 and 2 are the min and max
find if the signs go from negative to positive (min) or from positive to negative (max) at those points
f'(-1)>0
f'(1.5)<0
f'(3)>0
so at x=0, the sign go from positive to negative (local maximum)
at x=2, the sign go from negative to positive (local minimum)
we can take the 2nd derivitive to see the inflection points
f''(x)=2/((x-1)^3)
where does it equal 0?
it doesn't
so no inflection point
but, we can test it at x=0 and x=2
at x=0, we get f''(0)<0 so it is concave down. that means that x=0 being a max makes sense
at x=2, we get f''(2)>0 so it is concave up. that means that x=2 being a max make sense
local max is at x=0 (the point (0,0))
local min is at x=2 (the point (2,4))
