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2 years ago

Write an explanation on how to solve x-5.5=22.9

Mathematics

1 answer:

____ [38]2 years ago

7 0

Answer:

28.4

Step-by-step explanation:

Add 5.5 to both sides.

x - 5.5+5.5 cancels out the -5.5 to get x.

x = 22.9+5.5

x=28.4

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Did I set up the equation right? Please help me.

andrezito [222]

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5 0

3 years ago

A dollar bill weighs one gram. How many pounds do one million dollar bills weigh? (1000 grams

nata0808 [166]

Hey there! I'm happy to help!

First of all, if one bill weighs on gram, a million would weigh one million grams. Let's divide this by 1,000 to see how many kilograms it is.

1,000,000/1,000=1,000

Now, we need to convert 1,000 kilograms into pounds. We see that 1 kilogram is equal to about 2.205 pounds, so we multiply 1,000 kilograms by 2.205 to get our pounds.

1,000*2.205=2205

Therefore, one million dollar bills weigh about 2205 pounds.

Have a wonderful day! :D

5 0

3 years ago

use symbols to compare the numbers 512 and 521. write the comparison to ways. then explain your thinking

Morgarella [4.7K]

Solution:- Given numbers to compare are 512 and 521 .

As they are 3 digit numbers

So, we have to compare hundreds place.

But hundreds are equal in both the numbers with digit 5.

Next we have to compare tens place.

Case 1 :- 1 ten is smaller in 512 than 2 tens in 521 .

So we get the result that,

512 is smaller than 521

or <em> 512 < 521</em>

Case 2:-2 tens is greater in 521 than 1 ten in 512 .

So we get the result that,

521 is greater than 512

or <em> 521 > 512</em>

8 0

3 years ago

Write the number with 5 hundreds and 2 thousands

mina [271]

Answer:

500 2000

Step-by-step explanation:

6 0

2 years ago

Consider the following hypothesis test. H0: μ ≥ 55 Ha: μ < 55 A sample of 36 is used. Identify the p-value and state your con

Ket [755]

Answer:

Step-by-step explanation:

Given that:

$H_o: \mu \ge 55 \ \\ \\ H_1 : \mu < 55$

(a) For x = 54 and s = 5.3

The test statistics can be computed as:

$Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }$

$Z = \dfrac{54-55}{\dfrac{5.3}{\sqrt{36}} }$

$Z = \dfrac{-1}{\dfrac{5.3}{6} }$

Z = -1.132

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-1.132,35,1) = 0.1326

Decision: p-value is greater than significance level; do not reject $\mathbf{H_o}$

$Conclusion: \ There \ is \ insufficient \ evidence \ to \ conclude \ that \$ $\mu < 55$

For x = 53 and s = 4.6

The test statistics can be computed as:

$Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }$

$Z = \dfrac{53-55}{\dfrac{4.6}{\sqrt{36}} }$

$Z = \dfrac{-2}{\dfrac{4.6}{6} }$

Z = -2.6087

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-2.6087,35,1) =0.0066

Decision: p-value is < significance level; we reject the null hypothesis.

$Conclusion: \ There \ is \ sufficient \ evidence \ to \ conclude \ that$ $\mu < 55$

For x = 56 and s = 5.0

The test statistics can be computed as:

$Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }$

$Z = \dfrac{56-55}{\dfrac{5.0}{\sqrt{36}} }$

Z = 1.2

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(1.2,35,1) = 0.88009

Decision: p-value is greater than significance level; do not reject $\mathbf{H_o}$

$Conclusion: \ There \ is \ insufficient \ evidence \ to \ conclude \ that \$ $\mu < 55$

6 0

3 years ago