Answer:
2) 1
3) 9
4) 78
Step-by-step explanation:
2)
1 showed up the most
3)
range = max value - min value
range = 9 - 0
range = 9
4)
mode means which showed up the most,
78 showed up the most
First, given graph is very inaccurate. I suppose that you made net with pen.
a) The slope is the angle ( tan∡) between your graph and x axis.
The slope represent the level of the earnings growth.
b) According to the given graph y-intercept= 30$
Y-intercept represent starting amount of money.
c) If we accept that y=70 is connected with x=2 and y=30 with x=0
The slope is S= (70-30)/2= 40/2=20
Linear equation for this function is
y= 20x+30
d) When we replace y=300$ in the equation we get
20x+30=300 => 20x=300-30 => 20x=270 => x=270/20=13.5h
x=13.5h
Good luck!!!
-2 (x-2y=-5)
-2x+4y=10
2x+3y=4
0+7y=14
/7. /7
y=2
2x+3 (2)=4
2x+6=4
-6. -6
2x=-2
/2. /2
x=-1
Use the formula A = p( 1 + x)^n.
A = 1831.84(1 + 0.14)^6
You can finish.
The longest possible altitude of the third altitude (if it is a positive integer) is 83.
According to statement
Let h is the length of third altitude
Let a, b, and c be the sides corresponding to the altitudes of length 12, 14, and h.
From Area of triangle
A = 1/2*B*H
Substitute the values in it
A = 1/2*a*12
a = 2A / 12 -(1)
Then
A = 1/2*b*14
b = 2A / 14 -(2)
Then
A = 1/2*c*h
c = 2A / h -(3)
Now, we will use the triangle inequalities:
2A/12 < 2A/14 + 2A/h
Solve it and get
h<84
2A/14 < 2A/12 + 2A/h
Solve it and get
h > -84
2A/h < 2A/12 + 2A/14
Solve it and get
h > 6.46
From all the three inequalities we get:
6.46<h<84
So, the longest possible altitude of the third altitude (if it is a positive integer) is 83.
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