Answer:
C. Test for Goodness-of-fit.
Step-by-step explanation:
C. Test for Goodness-of-fit would be most appropriate for the given situation.
A. Test Of Homogeneity.
The value of q is large when the sample variances differ greatly and is zero when all variances are zero . Sample variances do not differ greatly in the given question.
B. Test for Independence.
The chi square is used to test the hypothesis about the independence of two variables each of which is classified into number of attributes. They are not classified into attributes.
C. Test for Goodness-of-fit.
The chi square test is applicable when the cell probabilities depend upon unknown parameters provided that the unknown parameters are replaced with their estimates and provided that one degree of freedom is deducted for each parameter estimated.
She can spend 6minutes with each friend.
Explanation step by step:
Maria has 30 min break, she walks 3 min to another floor- we have deduct that 3 min from 30 mi
30-3=27
Than she walks 3 min back to her floor
27-3=24
She has 24 minutes left which she equally divided between 4 friends
24:4=6
6 is the answer
Hi,
Negative, - 1/3 - 4/5 is subtracting a positive from a negative making it still a negative
They need to buy six because they will end up with fifty four.
(they cant buy five because they would end up with forty five and that wouldnt be enough)
Answer:She deposited $350.00 into the account at the beginning of the year.
Step-by-step explanation: