Cos(2
.
so...
Is that what you are trying to do? Find the zeros?
<h2>
<u>Answer</u>:</h2>
<h2><u>Explanation:</u></h2>
- Divide 1989 by 1989 to get 1
- Multiply 1 and 1 to get 1. Multiply 1 and 1 to get 1.
- And add 1 and 1 to get 2.
The equation y = |x-3| + |x+2| - |x-5| is an absolute value equation
The equivalent equation of y = |x-3| + |x+2| - |x-5| if -2 < x < 3 is y = x
<h3>How to rewrite the
absolute value equation?</h3>
The equation is given as:
y = |x-3| + |x+2| - |x-5|
The condition is given as:
if -2 < x < 3
Split and solve each term of the absolute value equation.
|x-3| = -(x - 3) = 3 - x....... because x < 3
|x+2| = x + 2 because -2 < x
|x-5| = -(x - 5) = 5 - x....... because x < 5
So, we have:
y = |x-3| + |x+2| - |x-5|
This gives
y = (3 - x) + (x + 2) - (5 - x)
Open the brackets
y = 3 - x + x + 2 - 5 + x
Evaluate the like terms
y = x
Hence, the equivalent equation of y = |x-3| + |x+2| - |x-5| if -2 < x < 3 is y = x
Read more about absolute value equations at:
brainly.com/question/12344256
I believe it’s B since both A and B are the same angle so the rest wouldn’t make sense