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ivann1987 [24]
3 years ago
7

Given ΔMNO, find the measure of ∠LMN.

Mathematics
2 answers:
Viefleur [7K]3 years ago
7 0

Answer:

Option D.

Step-by-step explanation:

Given information: MN ≅ NO

Isosceles triangle property : If two sides of a triangle and congruent then the angles opposite those sides are congruent.

Using Isosceles triangle property we get

\angle NMO\cong \angle NOM

Segment LM forming a straight angle with segment MO.

\angle LMN+\angle NMO=180

\angle NMO=180-\angle LMN

Segment OP forming a straight angle with segment MO.

\angle NOP+\angle NOM=180

\angle NOM=180-\angle NOP

Since \angle NMO\cong \angle NOM, so

180-\angle LMN\cong 180-\angle NOP

\angle LMN\cong \angle NOP

It is given that measure of angle NOP is 104 degree.

m\angle LMN=104^{\circ}

Therefore, the correct option is D.

Novay_Z [31]3 years ago
3 0

Answer:

  104°

Step-by-step explanation:

If segments NO and NM are congruent, then angles NMO and NOM are congruent. So, their supplements, angles NML and NOP are congruent. That is ...

  ∠NML ≅ ∠NOP = 104°

  ∠NML = 104°

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The domain of a function f(x)/m(x) = 1/√x(x² - 4) is (0, ∞) - {0, 2, -2} for other function is shown in the solution.

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It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have:

f(x) =  1/√x

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