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2 years ago

What is the length of the portion BC of the cloth?

Mathematics

1 answer:

alisha [4.7K]2 years ago

3 0

Answer:

2nd option

Step-by-step explanation:

Using the sine ratio in the right triangle

sin32° = $\frac{opposite}{hypotenuse}$ = $\frac{BC}{AC }$ = $\frac{BC}{6}$ ( multiply both sides by 6 )

6sin32° = BC

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darcy likes to eat peanut butter and raisins on apple slices. on each apple slice she puts 1/16 cup of peanut butter and 8 raisi

netineya [11]

The answer is 7/10.

For one apple slice, Darcy needs 1/16 cup of peanut butter and 8 raisins. She has 2/5 cup of peanut butter. To compare how many butter she has and she needs we will divide 2/5 with 1/1

This means that Darcy needs 5/80 cup of peanut butter and 8 raisins.
If she has 32/80 cup of peanut butter, she will have it only fo 6 or 7 apple slices (32/80 ÷ 5/80 = 6.4) depending how it is rounded. If she prepares 6 apple slices, she will still have a little of peanut butter left (0.4 = 2/5 of cup). So, she will prepare 7 apple slices so the butter will be all gone.

For 7 apple slices, she needs 56 raisins (7 × 8 raisins).
That is 56 raisins out of 80 raisins, so fraction of the 80 raisins did she eat is:
 $\frac{56}{80} = \frac{7}{10}$

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3 years ago

The number of transistors per square inch on an integrated chip doubles every 18 months. this observation is known asâ ________

Yanka [14]

Moore's Law
Source:
https://en.wikipedia.org/wiki/Moore%27s_law

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3 years ago

Name the property. 6 + 0 = 6

Rashid [163]

Answer:

The Identity property of addition

Step-by-step explanation:

The identity property of addition states that any number plus zero equals the original number. So, since 0 is being added to 6, it must still be equal to 6. This property works for any number, which is why it works as a property.

This is not to be confused with the identity property of multiplication that states that any number times 1 equals the original number.

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3 years ago

Sin^2x-cos^2x=0 solve for the equation for the interval [0, 2pi)

loris [4]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2088291

_______________

Solve the trigonometric equation:

$\mathsf{sin^2\,x-cos^2\,x=0}\qquad\qquad\mathsf{x\in [0,\,2\pi).}\\\\ \mathsf{(1-cos^2\,x)-cos^2\,x=0}\\\\ \mathsf{1-2\,cos^2\,x=0}\\\\ \mathsf{1=2\,cos^2\,x}\\\\ \mathsf{cos^2\,x=\dfrac{1}{2}}$

$\mathsf{cos\,x=\pm\,\sqrt{\dfrac{1}{2}}}\\\\\\ \mathsf{cos\,x=\pm\,\dfrac{1}{\sqrt{2}}}\\\\\\ \mathsf{cos\,x=\pm\,\dfrac{1}{\sqrt{2}}\cdot \dfrac{\sqrt{2}}{\sqrt{2}}}\\\\\\ \mathsf{cos\,x=\pm\,\dfrac{\sqrt{2}}{2}}$

$\begin{array}{lcl} \footnotesize\begin{array}{l}\bullet\end{array}~~\mathsf{cos\,x=-\,\dfrac{\sqrt{2}}{2}}&\quad\Rightarrow\quad&\mathsf{x=\pi-\dfrac{\pi}{4}~~or~~x=\pi+\dfrac{\pi}{4}}\\\\ && \mathsf{x=\dfrac{4\pi}{4}-\dfrac{\pi}{4}~~or~~x=\dfrac{4\pi}{4}+\dfrac{\pi}{4}}\\\\ && \mathsf{x=\dfrac{3\pi}{4}~~or~~x=\dfrac{5\pi}{4}}\qquad\quad\checkmark\\\\\\ \footnotesize\begin{array}{l}\bullet\end{array}~~\mathsf{cos\,x=\,\dfrac{\sqrt{2}}{2}}&\quad\Rightarrow\quad&\mathsf{x=\dfrac{\pi}{4}~~or~~x=2\pi-\dfrac{\pi}{4}}\\\\ && \mathsf{x=\dfrac{\pi}{4}~~or~~x=\dfrac{8\pi}{4}-\dfrac{\pi}{4}}\\\\ && \mathsf{x=\dfrac{\pi}{4}~~or~~x=\dfrac{7\pi}{4}}\qquad\quad\checkmark \end{array}$

Solution set: $\mathsf{S=\left\{\dfrac{\pi}{4},\,\dfrac{3\pi}{4},\,\dfrac{5\pi}{4},\,\dfrac{7\pi}{4} \right\}.}$

I hope this helps. =)

Tags: solve trigonometric trig equation sine cosine sin cos identity trigonometry

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3 years ago

Is -1i equal to the square root of 1? or something else...

Leya [2.2K]

No, 1 is the square root of 1

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3 years ago

What is the length of the portion BC of the cloth? ​

What is the length of the portion BC of the cloth?